Answer with Step-by-step explanation:
Suppose that a matrix has two inverses B and C
It is given that AB=I and AC=I
We have to prove that Inverse of matrix is unique
It means B=C
We know that
B=BI where I is identity matrix of any order in which number of rows is equal to number of columns of matrix B.
B=B(AC)
B=(BA)C
Using associative property of matrix
A (BC)=(AB)C
B=IC
Using BA=I
We know that C=IC
Therefore, B=C
Hence, Matrix A has unique inverse .
Answer:
40 is the answer
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Step-by-step explanation:
Important: Use the symbol "^" to denote exponentiation:
<span>x3 – 9x2 + 5x – 45 NO
</span><span>x^3 – 9x^2 + 5x – 45 YES
Look at the first 2 terms. They can be rewritten as x^2(x-9). Then look at the last 2 terms. They can be rewritten as 5(x-9). So, x-9 is the common factor here. Thus, the original expression becomes:
(x^2-5)(x-9).
Note that x^2-5 can be factored, so that the final 3 factors are:
(x-sqrt(5)), (x+sqrt(5)), (x-9).</span>
Answer:
64 inches
Step-by-step explanation:
5 * 12 = 60
60 + 4 = 64