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Lesechka [4]
3 years ago
13

A soccer club had 22 members with a mean age of 19.
Then 22 new members joined. One is 17 years old, and the other is

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

Step-by-step explanation:

number of members=22

mean age=19 years

Total age of 22 members=22×19=418 years

age of new members=17 years and 30 years

Total age of 24 members=418+17+30=465 years

mean=465÷24=19.375 years

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26

Step-by-step explanation:

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Which statement is true
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Step-by-step explanation: for a solution to occur the lines have to cross

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Jenny is 13 years older than her sister myra myra is 6 years younger than her sister melody their combined age is equal to 88 ye
il63 [147K]
X : Myra age
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Read 2 more answers
Company A: $39.99 per month no installation fee
Svetlanka [38]

Company A represents a proportional relationship, while company B does not.

<h3>Proportional relationship</h3>

The general format of a equation representing a proportional relationship is given as follows:

y = rx.

A proportional relationship is a special case of a linear function, having an intercept of zero.

Then, the output variable y is calculated as the multiplication of the input variable x by the constant of proportionality k.

The costs for each company after x months, in this problem, are represented as follows:

  • A(x) = 39.99x.
  • B(x) = 34.99x + 50.

Company B has an intercept different of zero, hence it is not a proportional relationship, while Company A, with an intercept of zero, represents a proportional relationship.

<h3>Missing Information</h3>

The complete problem is:

Two companies offer digital cable television as described below.

Company A: $39.99 per month no installation fee

Company B: $34.99 per month with a $50 installation fee

For each company tell whether the relationship is proportional between months of service and total cost is a proportional relationship. Explain why or why not

More can be learned about proportional relationships at brainly.com/question/10424180

#SPJ1

6 0
1 year ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
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