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dusya [7]
3 years ago
10

Find the exact value of each of the remaining trigonometric functions of theta when tan theta = -3/4

Mathematics
1 answer:
krok68 [10]3 years ago
8 0

Step-by-step explanation:

sinΘ=-3,cosΘ=4,cotΘ=-4/3,secΘ=1/4 & cosecΘ=-1/3

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Find the capacity of the tanks with the following internal dimensions. Express the capacity in cubic meters and liters for each
Vladimir [108]

Step-by-step explanation:

i) Capacity(Volume) = length x breadth x depth

= 3.2 x 2.9 x 1.5

= 13.92 m³

In litres, 13.92 x 1000 = 139,20 litres

ii) Capacity(Volume) = length x breadth x depth

= 2.5 x 1.6 x 1.3

= 5.2 m³

In litres, 5.2 x 1000 = 5200 litres

iii) Capacity(Volume) = length x breadth x depth

= 7.3 x 3.6 x 1.4

= 36.792 m³

In litres, 36.792 x 1000 = 36,792 litres

3 0
3 years ago
Solve the system by substitution.<br> 1. y = -6x – 7<br> y = -7x <br><br> 2. -y=x<br> 3x+5y=20
Drupady [299]

Answer:

For no. 1:

One of the equations say that y=-7x

So plug in -7x to the other equation as y so you equation would be

-7x= -6x-7

And then, just solve for the variable:

*add -6x to both sides*:

-x= -7

*multiply both by negative one to get a positive variable*

FOR NUMBER 1, THE ANSWER IS:

x=7

Y=-7

For no. 2:

-y=x and your other equation is 3x+5y=20

Plug in x as -y:

-3y+5y=20

*simplify*

2y=20

*divide by 2 on each side to get 1 variable alone*

Y=10

FOR NUMBER 2, THE ANSWER IS:

x=-y

Y=10

8 0
3 years ago
Write each as a percent. Round to the nearest tenth of a percent
Ghella [55]

Answer:

4. 3.1% this could be 0% either idk bc 0.031 rounded to nearest 10th is 0

6. 90%

8.10%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How are exponents and powers different?<br> (DON'T GOOGLE IT!)
Rasek [7]

Answer:

The power is larger than the exponet

Step-by-step explanation:

5 0
2 years ago
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The graph below represents the solution set of which inequality? x2 – 2x – 8 0 x2 + 2x – 8 &gt; 0
abruzzese [7]

Answer: x^2+2x-8<0

Step-by-step explanation:

A. x^2 - 2x - 8 < 0

(x - 4)(x + 2) < 0

B. x^2 + 2x - 8 < 0

(x + 4)(x - 2) < 0

C. x^2 - 2x - 8 > 0

(x - 4)(x - 2) > 0

D. x^2 + 2x - 8 > 0

(x + 4)(x - 2) > 0

When you test a point in the interval between -4 and 2, for example 0, it is negative.

8 0
3 years ago
Read 2 more answers
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