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elixir [45]
2 years ago
14

NO NEED FOR LINKS NEED HELP RIGHT NOW

Mathematics
2 answers:
SVEN [57.7K]2 years ago
8 0
  • 1 m = 0.001 Km
  • 1 Km = 1000 m
  • 1 ml = 0.001 L
  • 1 L = 1000 ml
  • 1 g = 0.001 Kg
  • 1 Kg = 1000 g
  • 1 mm = 0.01 cm

  1. a. 2000 m = 2 Km b. 9 Km = 9000m
  2. a. 9000 ml = 9 L b. 3 Kg = 3000 g
  3. a. 6 L = 6000 ml b. 90 mm = 0.9 cm

Hope you could get an idea from here.

Doubt clarification - use comment section.

Softa [21]2 years ago
4 0

Answer:

1a.2

2a. 9

3a. 6000

1b. 9000

2b. 3000

3b. 9

Step-by-step explanation:

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zepelin [54]
Hope this helps tried to color code it

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3 years ago
Fill in the blanks to make true number sentences.<br><br> 1 3/5 = __ : __
arsen [322]

Answer:

1 6/10

Step-by-step explanation:

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6 0
3 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview
mario62 [17]

Answer:  The required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

Step-by-step explanation:   We are given to solve the following differential equation :

5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.

So, the general solution of the given equation is

y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.

Differentiating with respect to t, we get

y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.

According to the given conditions, we have

y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

and

y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.

From equation (ii), we get

B=\dfrac{7}{3}.

Thus, the required solution is

y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.

7 0
3 years ago
Which of the following shows the numbers in the box below listed in increasing order?
Anarel [89]

9514 1404 393

Answer:

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Step-by-step explanation:

The numbers are in increasing order when they are listed left-to-right as they appear on the number line.

The only numbers that may give you trouble are 3/7 = 6/14 and 1/2 = 7/14.

The negative number is less than any positive number. 1.2 is greater than any fraction that is less than 1.

The correct ordering is found in choice A.

5 0
2 years ago
20n^2t / 5n^t what is the answer? and y?
Anastasy [175]
I hope this helps you

6 0
3 years ago
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