Answer: 560
Step-by-step explanation:
There are [20, 22, 24, 26, 28]: 5 even integers for each ten numbers.
The 20's set can be written as 5*20 + (2+4 + 6 + 8) = 5*20 + (20) = 120
The 30's can be written: 5*30 + 20 = 170
40's: 5*40+20 = 220
50's: 5*50+20 = 270
60's: 5*60+20 = 320
Each set is incremented by 50
We want the sets for 20, 30, and 40, plus the number 50.
(120+170+220+50) = 560
You can also do this in Excel (attached). Set the first cell to 20, the next cell below equal to the cell above plus 2. Then draw the second cell down until you've reached 50. Then sum the cells to arrive at 560.
Answer:
-7/6
Step-by-step explanation:
var y/ var x
5 to -2 is variation y ----> -7
-3 to 3 is variation x ---> 6
To find the length of the diagonal, we need to calculate the length of the base first and then use the value to calculate the diagonal since we are given the value of height of the triangle.
<h3>Pythagorean Theorem</h3>
This theorem is used to find the missing side of a right angle triangle given that we have the length of two sides.
To calculate the base of the triangle, let's use Pythagorean theorem here
Having the length of the base, let's consider the height of the triangle which is 6 and substitute the values.
From the calculations above, the values of the triangle are
- diagonal = 7
- base = 3.61
- height = 6
Learn more on pythagorean theorem here;
brainly.com/question/231802
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An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content…
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side.
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day.
