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VikaD [51]
2 years ago
6

In the chemical formula below, how many H atoms are present? 5NH4OH

Chemistry
1 answer:
Norma-Jean [14]2 years ago
8 0

Answer:

5 H atoms per NH4OH

Explanation:

5NH4OH

NH4OH is a chemical formula.  It has 5 H atoms per each molecule.  NH<em><u>4</u></em>O<em><u>H</u></em>

<em><u /></em>

5NH4OH means 5 molecules (or moles) of NH4OH.  But the question asks per chemical formula, so 5 is correct,

There would be 5x4 or 20 atoms of H is 5 molecules of NH4OH.

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Which intermolecular forces do the particles in the image (F– in water) experience? Note that the ion is not necessarily drawn t
Lena [83]

hydrogen bonding and ion-dipole

Explanation:

The intermolecular forces the particles of fluoride experiences is an ion-dipole bond, between the water molecules, there are hydrogen bonds.

  • An ion-dipole bond is an attractive force between an ion and a polar molecule.
  • The fluoride is the anion that is attracted by the positive end of water molecules.
  • Water is a polar compound.
  • Between the water molecule, there is presence of hydrogen bonds.
  • Hydrogen bonds are special dipole - dipole attraction between polar molecules joined to a highly electronegative atom.
  • The electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom of a neighboring molecule forms the hydrogen bond.

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3 0
3 years ago
How many variance electrons in Aluminium? Is it 3
ololo11 [35]

Answer:

Question #1: How many valence electrons in Aluminum? Is it 3?

------> Yes, aluminum has 3 valence electrons.

Question #2: How many valence electron in Sulfur? Is it 6?

-----> Yes, sulfur has 6 valence electrons.

Question #3: What type of bonds do these form? Is it covalent or ionic?

-----> Covalent bonds generally occur between 2 nonmetals. Ionic bonds generally occur between a metal and a nonmetal. Aluminum is a metal and sulfur is a nonmetal. Therefore, an ionic bond would form.

Question #4: How many aluminum atoms will you need? 1, 2, or 3?

-----> Atoms become ions in order to achieve a full octet of valence electrons (8 valence electrons). Since aluminum atoms have 3 valence electrons, they are likely to donate these electrons during ionization. As such, aluminum ions look like this: Al³⁺. Since sulfur atoms have 6 valence electrons, they are likely to receive 2 electrons during ionization. As such, sulfur ions look like this: S²⁻.

-----> The ionic compound formed will be Al₂S₃. There would be 2 aluminum atoms because this arrangement allows for the ionic compound to have an overall charge of 0.

Aluminum = +3

Sulfur = -2

+3 + 3 + (-2) + (-2) + (-2) = 0

Question #5: How many sulfur atoms will you need? 1, 2, or 3?

-----> As stated previously the resulting ionic compound is Al₂S₃. There would be 3 sulfur atoms to balance the charges.

6 0
2 years ago
All the oxides of nitrogen have positive values of G at 298K but only one common oxide of nitrogen has a positive S identify tha
Maurinko [17]

Answer:

The common oxide of nitrogen that has a positive ΔS°f is nitric oxide (NO)

Explanation:

Without reference to thermodynamic data, we have;

1) N₂ (g) + O₂ (g) ⇄ 2 NO (g)

1 unit of N₂ + 1 unit of O₂ (total of 2 units) gives 2 units of NO, (Increase of +0 disorder)

∴ΔS°f = +ve

2) 2NO + O₂ → 2NO₂

2 unit of NO + 1 unit of O₂ (total of 3 units) gives 2 units of NO₂, (Decrease of disorder)

∴ΔS°f = -ve

3) N₂ + 1/2 O₂ → N₂O

1 unit of N₂ + 1/2 unit of O₂ (total of 1+1/2 units) gives 2 units of NO₂, (Decrease of disorder)

∴ΔS°f = -ve

4) 4 NO₂ + O₂ → 2N₂O₅

4 unit of NO₂ + 1 unit of O₂ (total of 5 units) gives 2 units of N₂O₅, (Decrease of disorder)

∴ΔS°f = -ve

5) NO + NO₂ ⇄ N₂O₃

1 unit of NO + 1 unit of NO₂ (total of 2 units) gives 1 unit of N₂O₃, (Decrease of disorder)

∴ΔS°f = -ve

Therefore, the common oxide of nitrogen that has a positive ΔS°f without reference to thermodynamic data is nitric oxide NO.

6 0
3 years ago
A(n) __________ is formed when one atom loses an electron and another atom accepts that electron.
Roman55 [17]
The answer is a cation
8 0
3 years ago
In a halocarbon substituent are-<br> 1)metals<br> 2)non-metals<br> 3)Halogens<br> 4)noble gases
AveGali [126]

Answer:

Hey The answer is Halogens

6 0
3 years ago
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