I would think that all but one point would be on the line. One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation. Next time, would you please enclose the coordinates of each point inside parentheses: (2.5,14), (2.25,12), and so on, to avoid confusion.
14-12
slope of line thru 1st 2 points is m = ---------------- = 2/0.25 = 8
2.50-2.25
What is the eqn of the line: y = mx + b becomes
14 = (8)(2.5) + b; find b:
14-20 = b = -6. Then, y = 8x - 6.
Now determine whether (12,1.25) lies on this line.
Is 1.25 = 8(12) - 6? Is 1.25 = 90? No. So, unless I've made arithmetic mistakes, (1.25, 5) does not lie on the line thru (2.5,14) and (2.25,12).
Why not work this problem out yourself using my approach as a guide?
Answer:
3x+4y=20
Step-by-step explanation:
The slope-intercept equation would be:
y=mx+b
y=-3/4(x)+5
But standard form is
ax+by=c
We can obtain this by moving the -3/4(x) to the left side
Multiply both sides by 4 to get rid of the fraction
3x+4y=20
Answer: D) Inverse does not exist
<u>Step-by-step explanation:</u>
The top row is 0 0 , which makes the determinant equal to zero.
The reciprocal of 0 is undefined so there cannot be an inverse for this matrix.
Put in slope intercept form so the first equation would be y=-x-9 then the second one will be y=-5/2x-16
