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A rightward change in equilibrium.
The concentration of gases = [H2] will decrease, [N2] will increase, [NH3] will increase when the new equilibrium is reached.
Additional heat is produced.
The forward and backward reactions' rates quicken in the new equilibrium.
The equilibrium constant decreases as more heat is released.
the exothermic nature of the process.
The equilibrium constant would not have changed if the temperature had remained constant.
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Answer:
-74.6 kj/mol
Explanation:
you can see the answer at the pic
Data:
V1 = 6.7 liter
T1 = 23° = 23 + 273.15 K = 300.15 K
P1 = 0.98 atm
V2 = 2.7 liter
T2 = 125° = 125 + 273.15 K = 398.15 K
P2 = ?
Formula:
Combined law of ideal gases: P1 V1 / T1 = P2 V2 / T2
=> P2 = P1 V1 T2 / (T1 V2)
P2 = 0.98 atm * 6.7 liter * 398.15 K / (300.15K * 2.7 liter)
P2 = 3.22 atm