Answer:
moles B = 2.32 moles
Explanation:
In this case, we can assume that both gases are ideals, so we can use the expression for an ideal gas which is:
PV = nRT
From here, we can calculate the total moles (n) that are in the container, and then, by difference, we can calculate how much we have of gas B.
For this case, we will use R = 0.082 L atm / mol K. Solving for n:
n = PV/RT
n = 5 * 20 / 0.082 * 303
n = 4.02 moles
If we have 4.02 moles between the two gases, and we have 1.70 from gas A, then from gas B we simply have:
Total moles = moles A + moles B
moles B = Total moles - moles A
moles B = 4.02 - 1.70
moles B = 2.32 moles
We have 2.32 moles of gas B
Answer:
5.47 x 10^23 atoms in Ag (sliver)
Explanation:
0.909 mol of Ag x 6.02 x 10^23 atoms of Ag/ 1 mol of Ag
Answer:
C) 11 g
Explanation:
first look to graph , you have x and y
x is mass of Fe
and y is mass of product
if the reaction consumes 2 g of Fe , ( look to x axis , look to 2 )
and go up until the black line touch the line of number 2
and go left and you will see the point become in the middle between 10 and 12
** 12 (11) 10 ***
Good Luck
Magma, if it's the picture I know of then it would be "C"
