H2SO4 ---> 2H^+ + SO4^2-
Hence n H+ = 9 mols
Mass of H = nM = (9*1) = 9g
Alternately
mass of H2SO4= nM= 4.5*98= 441
Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g
Answer:
6.02 x 10²³ electrons
Explanation:
Given parameters:
Mass of H₂ = 2g
Unknown:
Number of electrons = ?
Solution:
To find the number of electrons, we must determine the number of moles of H₂ first.
Number of moles =
Molar mass of H₂ = 2(1) = 2g/mol
Number of moles =
= 1mol
1 mole of a substance contains 6.02 x 10²³ particles
the particles can be protons, neutrons, electrons
So,
2g of H₂ will contain 6.02 x 10²³ electrons.
Answer:
a. 10.54
Explanation:
reaction is
NH₃ + NaOH -----------------NH₄Cl + H₂O
0.10 mol NaOH will consume 0.10 mol NH₃ thereby decreasing the initial amount of moles NH₃ and increasing that of NH₄Cl
mol NH₃ = 0.80 - 010 = .70
mol NH₄Cl = 0.80 + .10 = 0.90
pH = pKₐ + log (( NH₃/NH₄Cl))
pH = 9.26 + log (( 0.90 + 0.70)) = 9.26 + 0.11 = 10.54