The answer is B) particles move faster.
Answer:
1255.4L
Explanation:
Given parameters:
P₁ = 928kpa
T₁ = 129°C
V₁ = 569L
P₂ = 319kpa
T₂ = 32°C
Unknown:
V₂ = ?
Solution:
The combined gas law application to this problem can help us solve it. It is mathematically expressed as;
P, V and T are pressure, volume and temperature
where 1 and 2 are initial and final states.
Now,
take the units to the appropriate ones;
kpa to atm, °C to K
P₂ = 319kpa in atm gives 3.15atm
P₁ = 928kpa gives 9.16atm
T₂ = 32°C gives 273 + 32 = 305K
T₁ = 129°C gives 129 + 273 = 402K
Input the values in the equation and solve for V₂;
V₂ = 1255.4L
When the atmospheric pressure is equal to the vapor pressure of the liquid, boiling of liquid will begin.
<h3>What happens when atmospheric pressure is equal to the vapor pressure of liquid?</h3>
When the atmospheric pressure is equal to the vapor pressure of the liquid, boiling will begin. The bubbles formation started to the liquid molecules which have gained enough energy to change to the gaseous phase.
The vapor pressure of ethanol is 5.95 kPa at 20.0 °C, and its vapor pressure is 53.3 kPa at 63.5 °C.
Learn more about pressure here: brainly.com/question/25965960
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