The answer is A. Hope this helped
Answer:
<u>167.2 g</u>
Explanation:
Known
VC4H10 = 21.3
T = 0.00 C (convert to Kelvin: 273 K)
P = 1.00 atm
Unknown
m = ?g
1. <u>Write the balanced chemical equation</u>
1 C4H10 + 1O2 -----> 4 CO2 + 5 H2O
2. <u>Find the volume ratio of Carbon Dioxide to Butane </u>
1 C4H10 4 CO2 = 4 volumes CO2 / 1 volume C4H10
3.<u> Multiply by the known volume of n (butane)</u>
21.3 L C4H10 x 4 volumes CO2 / 1 volume C4H10 = 85.2 L C4H10
4. <u>Use ideal gas law</u>
PV = nRT solve for n ----> n = PV/RT
n= (1.00 atm) (85.2 L) / (0.0821 L atm/mol K) (273) = 3.80 mol CO2
5.<u> Find molar mass of CO2</u>
1 C x 12 + 2 O x 16 = 44.00
6. <u>Multiply the ideal gas law solution (3.80) by molar mass CO2 (44.00)</u>
3.80 mol CO2 x 44.00 g CO2
= 167.2 g CO2
CH4 + O2 = CO2 + H2O - Chemical Equation Balancer.
Answer:
The answer is 1.778*10^-9
Explanation:
Using the formula
pH = -log[H^+]
Since the pH of the solution has been given to be 8.75,
Therefore,
8.75= -log [H^+]
Let's take H^+ to be x
8.75= -log x
Let's look for x, since the log is in base 10
X = 10^-8.75
X = 1.778 * 10^ -9
Therefore, H^+ =1.778 *10^-9