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Tema [17]
3 years ago
6

Consider the following set of equations:

Mathematics
1 answer:
serious [3.7K]3 years ago
8 0
Since Y equals BOTH (-X+5) and (6X-2), you can set the two equations equal to eacher other; therefore, the answer is: C: -X+5=6X-2

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I don’t understand the question..?
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2 years ago
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How would you write the following expression as a sum or difference? `"log"(root(3)(2 - x)/(3x))`
pashok25 [27]

<h3>log [ (√3)(2 - x)/(3x) ] = log (2 - x) - ¹/₂ log 3 - log x</h3>

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

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3 years ago
Sketch the graph for each function. Choose either A, B, C, or D.
Serjik [45]
Hi. Here it is!
I hope this help...

—> And the answer is letter A

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2 years ago
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katovenus [111]

Answer:

Step-by-step explanation:

K is located at -25

L is located at -15

just move 5 units away from J on both sides

hope this helps <3

5 0
3 years ago
Which is an irrational number?<br><br> 0/3<br> 4.37124<br> 5.2<br> /42.25
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43.5 is the answer to the question
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2 years ago
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