Answer : The equilibrium concentration of will be, (C)
Explanation : Given,
Equilibrium constant = 14.5
Concentration of at equilibrium = 0.15 M
Concentration of at equilibrium = 0.36 M
The balanced equilibrium reaction is,
The expression of equilibrium constant for the reaction will be:
Now put all the values in this expression, we get:
Therefore, the equilibrium concentration of will be, (C)
Explanation:
(A) As we know that carbonic acid () and Sodium bicarbonate (
) forms an acidic buffer.
Therefore, pH of an acidic buffer is given by Hendeerson-Hasselbalch equation as follows.
pH = ........... (1)
So mathematically, if [Salt] = [Acid] then = 1
.
And, = 0
Therefore, equation (1) gives us the following.
pH = (when acid and salt are equal in concentration)
Hence, of
(carbonic acid) is 6.35.
And, with this we have following results.
In (A) and (D) we have the case \frac{[NaHCO_{3}]}{[H_{2}CO_{3}]}[/tex] i.e. [Salt] = [Acid].
Hence, for the cases pH = = 6.35.
(B) = 0.045 M and,
= 0.45 M
Hence, pH =
=
= 6.35 + (-1)
= 5.35
Therefore, it means that this buffer will be most suitable buffer as it has pH on acidic side and addition of slight excess base will not affect much of its pH value.
(C) = 0.45 M
= 0.045 M
So, pH =
=
= 6.35 + (+1)
= 7.35
This means that pH on Basic side makes it no more acidic buffer.
Answer:
Explanation:
Hello,
In this case, since the rms speed of the molecules is computed by:
Whereas the absolute temperature is computed from the internal energy (by using the Cp of helium (3.1156 J/g*K) as shown below:
Thereby, the rms speed results:
Regards.