The maximum oxygen uptake is known as the __________.
2 answers:
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First a balanced reaction equation must be established:
→ 
Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
= 4.83 mols
Now the mole ratio of Al : O₂ based on the equation is 4 : 3
[4Al + 3 O₂ → 2 Al₂O₃]
∴ if moles of Al = 4.83 moles
then moles of O₂ = (4.83 mol ÷ 4) × 3
= 3.63 mol (to 2 sig. fig.)
Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum.
Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
= 4.83 mols
Now the mole ratio of Al : O₂ based on the equation is 4 : 3
[4Al + 3 O₂ → 2 Al₂O₃]
∴ if moles of Al = 4.83 moles
then moles of O₂ = (4.83 mol ÷ 4) × 3
= 3.63 mol (to 2 sig. fig.)
Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum.
Answer:
2.67 x 10⁷km
Explanation:
Given parameters:
Time of arrival of p-waves = 2: 10: 00
Time of arrival of s-waves = 2: 15: 20
Unknown:
Distance of wave from epicenter = ?
Solution:
To find the distance of the wave from the epicenter;
Distance = 3 x 10⁸ x time interval
Time interval = Time of arrival of p-waves - Time of arrival of s-waves
= 2: 10: 00 - 2: 15: 20
= 5min 20s
= 320s
Now, we need to convert the time to hrs;
3600s = 1hr
320s = =
hr
So,
Distance = 3 x 10⁸ x = 2.67 x 10⁷km