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CaHeK987 [17]
3 years ago
10

The maximum oxygen uptake is known as the __________.

Chemistry
2 answers:
Tatiana [17]3 years ago
8 0

Answer:maximum oxygen

uptake is as the VO2 max

Explanation:

andrezito [222]3 years ago
4 0
The maximum oxygen uptake is known as the VO2 max.
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an apple pie needs 10 large apples, 2 crusts (top and bottom), one tablespoon of cinnamon. write a balanced equation that fits t
nasty-shy [4]
You're answer is 250 apples for 25 pies
4 0
3 years ago
Read 2 more answers
How many of the following molecules have sp2 hybridization on the central atom? hcn so2 ocl2 xecl2.
GrogVix [38]

Only one molecule have <u>sp2 </u>hybridization on central atom and that is <u>SO₂</u>.

<u>XeCl₂</u> have <u>sp3d </u>hybridization.

<u>OCl₂</u> have <u>sp3 </u>hybridization.

<u>HCN </u>have <u>sp </u>hybridization.

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.

Learn more about hybridization here:- brainly.com/question/22765530

#SPJ4

7 0
1 year ago
If you have 85g of sulfur dioxide at STP, how many moles do you have?
Step2247 [10]

Answer: 1.32

Explanation:

Given

85 gm of sulfur dioxide is present at STP

The molar mass of sulfur dioxide is 32+2\times 16=64\ g/mol

The number of moles of sulfur dioxide is

\Rightarrow n=\dfrac{85}{64}\\\\\Rightarrow n=1.32\ \text{mol}

3 0
3 years ago
(6 points) Calculate the maximum number of moles and grams of H2S that can form when 158 g of aluminum sulfide reacts with 131 g
Schach [20]

Answer:107.1 g, 124.1 g

Explanation:

The equation of the reaction is;

Al2S3(s) + 6H20(l) ----> 2Al(OH)3(s) + 3H2S(g)

Hence;

For Al2S3

Number of moles= reacting mass/molar mass

Number of moles = 158g/150gmol-1 =1.05 moles

If 1 mole of Al2S3 yields 3 moles of H2S

1.05 moles of Al2S will yield

1.05 × 3/1 = 3.15 moles

Mass of H2S = 3.15moles × 34 gmol-1 = 107.1 g

For water

Number of moles of water = 131g/18gmol-1= 7.3 moles

6 moles of water yields 3 moles of H2S

7.3 moles of water will yield 7.3 × 3/6 = 3.65 moles of H2S

3.65 moles × 34 gmol-1 =124.1 g

5 0
3 years ago
Determine the maximum amount of Fe that was produced during the experiment. Explain how you determined this amount.
dsp73

Answer:

5 moles of Fe

Explanation:

The equation of the reaction is;

2 Al(s) + Fe 2O 3(s) --> 2Fe (s) + Al 2O 3 (s)

Now;

1 mole of Fe2O3 require 2 moles of Al

3 moles of Fe2O3 requires 3 × 2/1 = 6 moles of Al

Hence Al is the limiting reactant.

If 2 moles of Al yields 2 moles of Fe

5 moles of Al yields 5 × 2/2 = 5 moles of Fe

5 0
2 years ago
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