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ira [324]
2 years ago
14

What is the chemical formula for the compound formed between rubidium and iodine?

Chemistry
1 answer:
IgorLugansk [536]2 years ago
3 0
Your answer must be: Rbi
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This is actually science but anyways my teacher didn't explain much can someone help?
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the radius of magnesium atom is 0.160nm. the radius of a magnesium ion is 7.2x 10^-11m. explain the difference in size between t
Allushta [10]

Answer:

during reaction magnesium lises ions.

Explanation:

magnesium reacts by losing two ions which makes it smaller in size.

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3 years ago
This is the process where fossil fuels, forests, or other carbon-containing substances are burned, adding more carbon dioxide to
sattari [20]
The process where fossil fuels, forests, or other carbon-containing substances are burned, addin more carbon dioxide to the air is the combustion.

Some examples of combustion are:

Fossil fuel:

Carbon + O2

C + O2 -> CO2

Forests (wood)

Wood = cellulose = [C6H10O5]n

[C6H10O5]n + 6nO2 = 6n CO2 + 5n H2O

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4 0
2 years ago
Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev
liq [111]

Answer: There will be 131.3 tons of SO_{2} that will be generated.


Explanation : We have the data as 72 tons of H_{2}S, O_{2} is 101 tons and H_{2}O as 38 tons.


Conversion of 1 ton to kg will be approximately 907.2 Kg


We have to convert the given data of tons into kg for all;


So, moles of H_{2}S = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X 10^{6} moles

Now, moles of O_{2} = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X10^{6} moles

And, H_{2}O = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X 10^{6} moles


Now, we have to calculate the moles of H_{2}S

so, 1.916 X 10^{6} moles / 2 moles of H_{2}S = 958 X 10^{3}


Now, for O_{2} ;

So, 2.80 X10^{6} moles / 3 moles of O_{2} = 933.3 X 10^{3} moles


Here, we can see that O_{2} is acting as a limiting reactant.


Now, moles of SO_{2} = 2.80 X10^{6} X (2 moles of SO_{2} / 3 moles of O_{2}) = 1.86 X 10^{6}


Now converting this into mass,


Mass = Moles X Molar Mass

Mass = 1.86 X 10^{6} X (64.066 g/mol X 10^{-3} kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of SO_{2}

7 0
3 years ago
Read 2 more answers
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