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melamori03 [73]
3 years ago
9

The reaction between ethanoic acid and solution hydroxide is an example of​

Chemistry
2 answers:
Tema [17]3 years ago
7 0
I think it would be neutralization reaction/acid-base reaction though I’m not 100% sure
Solnce55 [7]3 years ago
4 0

Answer:

See below.

Explanation:

I assume you mean sodium hydroxide.

This is an acid base reaction.

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What solid can be formed from a net diagram that has 2 congruent circles and 1 rectangle?
Serggg [28]

Answer: Option (B) is the correct answer.

Explanation:

When two circles are of same same then they are known as congruent circles.

Whereas a rectangle is a kind of parallelogram with all sides equal to 90^{o}.

Therefore, when 2 congruent circles and 1 rectangle combines then it results in the formation of a cylinder.

Thus, we can conclude that solid formed when 2 congruent circles and 1 rectangle combines will be a circle.

5 0
3 years ago
Read 2 more answers
Hello there!
Alenkasestr [34]

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃  →  Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃  with CO₂.

                   Li₂CO₃        :            CO₂

                     1                :               1

                  0.17             :             0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide =   0.17 mol ×  44 g/mol

Mass of carbon dioxide = 7.48 g

4 0
3 years ago
Which of the following statements is true?
Shtirlitz [24]

Answer: Elements in the last period are radioactive.

Explanation:

8 0
4 years ago
Read 2 more answers
alculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer. Express your answer using two decima
svetlana [45]

A 1.0-L buffer solution contains 0.100 mol  HC2H3O2 and 0.100 mol  NaC2H3O2. The value of Ka for HC2H3O2 is 1.8×10−5.

Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

Answer:

The pH of this solution = 5.06  

Explanation:

Given that:

number of moles of CH3COOH = 0.100 mol

volume of the buffer solution = 1.0 L

number of moles of NaC2H3O2 = 0.100 mol

The objective is to Calculate the pH of the solution, upon addition of 0.035 mol of NaOH to the original buffer.

we know that concentration in mole = Molarity/volume

Then concentration of [CH3COOH] = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  = 0.10 M

The chemical equation for this reaction is :

\mathtt{CH_3COOH + OH^- \to CH_3COO^- + H_2O}

The conjugate base is CH3COO⁻

The concentration of the conjugate base [CH3COO⁻] is  = \mathtt{ \dfrac{0.100  \ mol}{ 1.0  \  L }}  

= 0.10 M

where the pka (acid dissociation constant)for CH3COOH = 4.74

If 0.035 mol of NaOH is added  to the original buffer, the concentration of NaOH added will be = \mathtt{ \dfrac{0.035  \ mol}{ 1.0  \  L }} = 0.035 M

The ICE Table for the above reaction can be constructed as follows:

                  \mathtt{CH_3COOH \ \ \   +  \ \ \ \ OH^-  \ \ \to \ \ CH_3COO^-  \ \ \ + \ \ \  H_2O}

Initial             0.10               0.035         0.10                  -

Change        -0.035          -0.035       + 0.035              -

Equilibrium    0.065              0              0.135               -

By using  Henderson-Hasselbalch equation:

The pH of this solution = pKa + log \mathtt{\dfrac{CH_3COO^-}{CH_3COOH}}

The pH of this solution = 4.74 + log \mathtt{\dfrac{0.135}{0.065}}

The pH of this solution = 4.74 + log (2.076923077 )

The pH of this solution = 4.74 + 0.3174

The pH of this solution = 5.0574

The pH of this solution = 5.06    to two decimal places

7 0
3 years ago
A sample of sugar contains 1.505 × 1023 molecules of sugar. How many moles of sugar are present in the sample?
alisha [4.7K]
1 mole ------------ 6.02 x10²³ molecules
? mole ----------- 1.505 x10²³ molecules

1.505x10²³ / 6.02x10²³ => 0.25 moles

hope this helps!


4 0
3 years ago
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