<h2>
Hello!</h2>
The answer is:
A.
<h2>Why?</h2>
To solve the problem, we need to perform the shown operation.
We have the functions:
So, performing the following operation, we have:
Hence, we have that the correct option is:
A.
Have a nice day!
For this case what you should know is that all functions tend to infinity when x tends to infinity.
However, there are functions that grow faster than others.
In this case, the function that grows fastest is the one with the highest exponent.
We have then:
g (x) = 5x ^ 500
The exponent of 500 makes the function grow to infinity faster than the other functions.
Answer:
C) g (x) = 5x500
The idea is to use the zero product property in reverse to go from the roots to the factorization. Then you expand out the polynomial using the distributive property.
x = 5 or x = 7 or x = -8
x-5 = 0 or x-7 = 0 or x+8 = 0
(x-5)(x-7)(x+8) = 0
(x-5)(x^2+x-56) = 0
x(x^2+x-56) - 5(x^2+x-56) = 0
x^3+x^2-56x -5x^2-5x+280 = 0
x^3-4x^2-61x+280 = 0
f(x) = x^3 - 4x^2 - 61x + 280
<h3>Answer: Choice D</h3>
Answer:
I would need to see the grapgh
Step-by-step explanation:
Answer:
Option 2 is right
Step-by-step explanation:
Given that
We can write this in polar form with modulus and radius
Hence angle = 60 degrees and
Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360
Using Demoivre theorem we get 5th root would be
5th root of 2 multiplied by 1/5 th of 60, 420, 780,....
![z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\](https://tex.z-dn.net/?f=z%3D%20%5Csqrt%5B5%5D%7B2%7D%20%28cos12%2Bisin12%29%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos84%2Bisin84%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos156%2Bisin156%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos228%2Bisin228%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos300%2Bisin300%29%5C%5C)
Out of these only 2nd option suits our answer
Hence answer is Option 2.
