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2 years ago

Pleaseeee help meenpleaseeee!!!!!!!!

Mathematics

1 answer:

Iteru [2.4K]2 years ago

3 0

Answer:

-5/4

Step-by-step explanation:

4x-5y=10

-5y=-4x-10

-5y/-5=-4/-5-10/-5

y=4/5+2

perpendicular slope is -5/4

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You are making small pizzas. You have 12 cups of flour. Each pizza crust requires 3/

sveticcg [70]

Hello,

The answer is "16".

Reason:

Just divide 12 by 3/4:

12×4=48÷3=16
1×3=3÷3=1

16/1=16

Therefore they can make 16 pizza crusts!

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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3 years ago

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The graph represents a functional relationship. On a coordinate plane, a straight line with a negative slope begins at point (1,

Zepler [3.9K]

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3 years ago

A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho

MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

$Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16$

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

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3 years ago

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Write the expression as either the sine, cosine, or tangent of a single angle. tan5x - tan2y / 1 + tan5x tan2y

Kryger [21]

$\bf \textit{Sum and Difference Identities}
\\\\
tan(\alpha + \beta) = \cfrac{tan(\alpha)+ tan(\beta)}{1- tan(\alpha)tan(\beta)}
\qquad
tan(\alpha - \beta) = \cfrac{tan(\alpha)- tan(\beta)}{1+ tan(\alpha)tan(\beta)}\\\\
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6 0

3 years ago

In 2000, the population of Big Springs was 13 thousand. Use the given doubling

trasher [3.6K]

Answer:

The answer is "26179.4".

Step-by-step explanation:

Assume year 2000 as t, that is t =0.

Formula:

$A= A_0e^{rt}$

Where,

$A_0 = \ initial \ pop \\\\r= \ rate \ in \ decimal \\\\t= \ time \ in \ year$

for doubling time,

$r = \frac{log (2)}{t} \\$

$r = \frac{\log (2)}{ 40} \\\\r= \frac{0.301}{40}\\\\r= 0.007$

Given value:

$A = A_0e^{rt} \\\\$

$A_0 = 13000$

$t= 40 \ years$

when year is 2000, t=0 so, year is 2100 year as t = 100.

$A = 13000 \times e^{et}\\\\A = 13000 \times e^{e \times t}\\\\A = 13000 \times e^{0.007 \times 100}\\\\A = 13000 \times e^{0.7}\\\\A= 13000\times 2.0138\\\\A = 26179.4$

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3 years ago