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3 years ago

9

PLEASE HELP QUESTION IN PICTURE

2 answers:

nataly862011 [7]3 years ago

6 0

Area=119
The other dude gave the perimeter so I’ll give the area I got.
Just divide the whole area into two trapezoids and a rectangle.
Area of trapezoid is 1/2(a+b)*h. There are two trapezoids that are identical so just (a+b)/h
(5+11)*4=64
Add the area of the square.
5*11=55
Add together.
119

Stells [14]3 years ago

3 0

Answer:

Perimeter= 40

Area= 120.71

Step-by-step explanation:

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<em>C. 15 feet</em>

Step-by-step explanation:

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3 years ago

Solve the following system of equations<br>2x – 3y = 6<br>4x+2y=4

FinnZ [79.3K]

Answer:

$\boxed{(\frac{3}{2} ,-1)}$

Step-by-step explanation:

$\left \{ {{2x-3y=6} \atop {4x+2y=4}} \right.$

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Multiply everything in the first equation by -2 (we want the 4x to be able to cancel out with a -4x).

$2x-3y=6 \rightarrow -4x+6y=-12$

Now line up the equations (they are already lined up - convenient) and add them from top to bottom.

$\left \{ {{-4x+6y=-12} \atop {4x+2y=4}} \right.$

The -4x and 4x are opposites, so they cancel out.

Adding 6y and 2y gives you 8y, and adding -12 and 4 gives you -8.

$8y=-8$

Divide both sides by 8.

$y=-1$

Since you have the y-value you can substitute this in to the second (or first equation, it doesn't necessarily matter) equation.

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Simplify.

$4x -2=4$

Add 2 to both sides.

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Divide both sides by 4.

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