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elena-s [515]
2 years ago
11

What is the length of the line?

Mathematics
1 answer:
Radda [10]2 years ago
8 0

Answer:

x=\sqrt{169}

x=13

Step-by-step explanation:

12*12+5*5=x*x

x*x=169

x=\sqrt{169}

x=13

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Convert the expression 10-(-30) to an addition expression.
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Answer:

10 + 30

Step-by-step explanation:

if there are 2 negative signs they both cancel each other making it a positive, making the expression 10-(-30) into 10 + 30

Ps: Those 2 equations have the same answer

(could i have brainiest?)

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An article suggests that substrate concentration (mg/cm^3) of influent to a reactor is normally distributed with μ = 0.60 and σ
defon

Answer:

a)P(X>0.5)=P(\frac{X-\mu}{\sigma}>\frac{0.5-\mu}{\sigma})=P(Z>\frac{0.5-0.6}{0.08})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(z>-1.25)=1-0.106=0.894

b) P(X

And we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(z

c) z=1.64

And if we solve for a we got

a=0.6 +1.64*0.08=0.7312

So the value of height that separates the bottom 95% of data from the top 5% is 0.7312.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the substrate concentration of a population, and for this case we know the distribution for X is given by:

X \sim N(0.6,0.08)  

Where \mu=0.6 and \sigma=0.08

We are interested on this probability

P(X>0.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>0.5)=P(\frac{X-\mu}{\sigma}>\frac{0.5-\mu}{\sigma})=P(Z>\frac{0.5-0.6}{0.08})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(z>-1.25)=1-0.1056=0.8944

Part b

P(X

And we can use the z score formula given by:

z = \frac{x- \mu}{\sigma}

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(z

Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=0.6 +1.64*0.08=0.7312

So the value of height that separates the bottom 95% of data from the top 5% is 0.7312.  

4 0
3 years ago
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