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BlackZzzverrR [31]

2 years ago

14

15 divided by what makes 5

1 answer:

goldenfox [79]2 years ago

5 0

Answer:

3

Step-by-step explanation:

3*5=15

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What is d square root of 49

fomenos

Answer:

± 7

Step-by-step explanation:

Given

d = $\sqrt{49}$ , then

d = 7 or - 7, that is ± 7

Since 7 × 7 = 49 and - 7 × - 7 = 49

3 0

4 years ago

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What is zero of the polynomial and example

stich3 [128]

<span> Binomials and trinomials are two types of polynomials. The first has two terms and the second has three.</span>

8 0

4 years ago

Solve for x.<br><br> x=<br><br> Look at image

postnew [5]

Answer:

$x = 14$

Step-by-step explanation:

To find x, the following equation is generated given the available information:

$\frac{(x + 7) + x)}{x + 7} = \frac{12 + 8}{12}$

$\frac{2x + 7}{x + 7} = \frac{20}{12}$

$\frac{2x + 7}{x + 7} = \frac{5}{3}$

Cross multiply

$3(2x + 7) = 5(x + 7)$

$6x + 21 = 5x + 35$

Collect like terms

$6x - 5x = - 21 + 35$

$x = - 21 + 35$

$x = 14$

8 0

3 years ago

Can you answer this pls

Gnoma [55]

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7 0

3 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

4 years ago