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hodyreva [135]
2 years ago
12

The spinner is equally likely to land on any of the five sections. A spinner contains 5 equals sections labeled 1, 2, 3, 4, 5. S

ections 2, 1, 5, 4 are shaded. What is the probability that the spinner lands on an even number or on the unshaded section? One-fifth Two-fifths Three-fifths Four-fifths
Mathematics
1 answer:
Maurinko [17]2 years ago
8 0

Answer:

Three-fifths

Step-by-step explanation:

The number of sections is 5 and the unshaded section is 3 even numbers are 1, 3 and 5. Since 3 is in both cases there are 3 numbers: 1, 3 and 5. So it is three-fifths

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What is the measure of Zc<br>​
maks197457 [2]

Answer: 56 degrees

Step-by-step explanation:

We know that angle between b and c is 90 degrees. Because there is a line dividing angles a and b from 124 and c, we also know that each side is 180 degrees (a and b add to 180, and 124 and c add to 180).

124 and c are supplementary angles. We can represent this in an equation to solve for c:

124 + c = 180\\\\c = 56

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timurjin [86]

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Step-by-step explanation:

6 0
3 years ago
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A college student with a bachelors degree in nursing from an accredited institution has an 86.74% chance of getting hired full t
Vladimir79 [104]

Answer:

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Compute the probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

In this problem, we have that:

Event A: Completing their degree there.

There is a 34.72% chance of a student interested in a nursing degree not making it through the program.

So 100 - 34.72% = 65.28% = 0.6528 probability of completing their degree. So P(A) = 0.6528.

Event B: Getting hired

86.74% chance of getting hired full time in a hospital setting within 6 months of graduation.

Completing their degree and getting hired:

P(A \cap B) = 0.6528*0.8674

Probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.6528*0.8674}{0.6528} = 0.8674

86.74% probability of a Madonna University nursing student getting hired within 6 months of graduation given that they complete their degree here.

5 0
3 years ago
Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
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