Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)
Re-write both sides:
3^(4x-5) = 3^(-6x - 30)
from here, you can solve x
4x - 5 = -6x - 30
4x + 6x = -30 + 5
10x = -25
x = -2.5
Answer:
Step-by-step explanation:
4x-13
Answer:
21
Step-by-step explanation:
f(x) =x^2 - 6x + 21
f(xl =0
Answer:
substitute 0 for x
f(0) = 0^2 - 6(0) + 21
0. = 0 - 0 + 21
0. = 21