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Kazeer [188]
3 years ago
7

At Ben’s ice cream emporium, an ice cream cone costs $2.00 on weekends and $3.00 on weekdays. If you buy an ice cream cone every

day except Thursday, how much would you spend on ice cream that week?
Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0

Answer:

You would spend a total of $16 that week.

Step-by-step explanation:

# of weekdays besides Thursday: 4

# of weekends: 2

4x3=12

2x2=4

12+4= $16

Hope this helps! :)

<h3>CloutAnswers</h3>
Sauron [17]3 years ago
3 0

Answer:

$16

Step-by-step explanation:


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Help please it’s for a test I’m so clueless!!!!!!
kumpel [21]

Answer:

h=12  A=144 sq. cm.

Step-by-step explanation:

pythagoream therom:

9^2+h^2=15^2

81+h^2=225

h^2=225-81

h^2=144

Sq. rt h^2=sq. rt 144

h=12cm

1/2(b1+b2)h

1/2(5+19)12

1/2(24)12

1/2(288)

a=144

6 0
3 years ago
A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
The school store has 750 packs of crayons.each pack has 12 markers in it.how many markers are there in all
kirza4 [7]
There are 9,000 markers in total

750 x 12 = 9,000
3 0
3 years ago
Please help click on the image below
vodomira [7]
The answer should be 2
4 0
3 years ago
Read 2 more answers
Please help ASAP I might mark you brainliest
Tatiana [17]

Answer:

Where is the question or figure ???

5 0
2 years ago
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