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SpyIntel [72]
3 years ago
10

Diesel Inc. is making frames for a new product being launched at the end of the year. To keep the weight down, the area of the f

rame should be 18 cm2. The inside of the frame has to be 11 cm by 6 cm. What should the width of the frame be?
Mathematics
1 answer:
tresset_1 [31]3 years ago
7 0
To answer, allow the width of the frame to be represented by x. The dimensions of the frame should then be, 11+2x and 6+2x. Subtracting the area of the inside of the frame from the area of the outside should be able to give us 18 cm². The equation,
                              (11 + 2x)(6 + 2x) - (11)(6) = 18
The value of x from the equation is equal to  0.5. Thus, the width of the frame should be 0.5 cm. 
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<h3>We have to determine</h3>

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Expression; \rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)

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By applying the distributive property of multiplication;

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The equivalent expression is,

\rm 2(\dfrac{3}{4}x+7) -3(\dfrac{1}{2}x-5)\\&#10;\\&#10;\rm (2 \times \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\&#10;\\&#10;2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\

Hence, the expression is equivalent to \rm2( \dfrac{3}{4}x) + 2(7) -3(\dfrac{1}{2}x) + (-3) (-5)\\.

To know more about Equation click the link given below.

brainly.com/question/13174611

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