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navik [9.2K]
3 years ago
12

Please help ASAP I might mark you brainliest

Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

Where is the question or figure ???

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7
jeyben [28]

Answer:

x = -2

Step-by-step explanation:

Given the point, (-2, 9) and the linear equation of a <u>horizontal line</u>, y = 6:

The linear equation of a horizontal line with a slope of zero (<em>m</em> = 0) is y = <em>b, </em>for which the y-intercept is (0, <em>b</em>). <u>Perpendicular lines</u> comprise of the intersection of two lines forming 90° angles.  

Since we are given the equation of a horizontal line, then we can assume that <em>the line that intersects a horizontal line must be a </em><u><em>vertical line</em></u> in order to form perpendicular lines.

The linear equation of a <u>vertical line</u> with an undefined slope is <em>x</em> = <em>a</em>, for which the x-intercept is (<em>a</em>, 0). Vertical lines have an <u>undefined slope </u>because these lines do not have any horizontal change. Thus, when you try to solve for its slope, the denominator will have a difference of 0, making the mathematical operation undefined.

We can use the <u>x-coordinate</u> of the given point, (-2, 9), to formulate an equation for a vertical line: x = -2.

Therefore, the equation of the line that goes through y = 6 is x = -2.

Attached is a screenshot of the graph of both equations, y = 6 and x = -2, showing that their intersection form 90° angles, making them perpendicular lines.      

8 0
3 years ago
What number x makes the equation 8 to the power of x = 2 correct?
Daniel [21]
<span>A linear equation in one variable has a single unknown quantity called a variable represented by a letter. Eg: ‘x’, where ‘x’ is always to the power of 1. This means there is no ‘ x² ’ or ‘ x³ ’ in the equation.The process of finding out the variable value that makes the equation true is called ‘solving’ the equation.An equation is a statement that two quantities are equivalent.For example, this linear equation:  x<span> + 1 = 4 </span>means that when we add 1 to the unknown value, ‘x’, the answer is equal to 4.To solve linear equations, you add, subtract, multiply and divide both sides of the equation by numbers and variables, so that you end up with a single variable on one side and a single number on the other side. As long as you always do the same thing to BOTH sides of the equation, and do the operations in the correct order, you will get to the solution.</span><span><span>For this example, we only need to subtract 1 from both sides of the equation in order to isolate 'x' and solve the equation:x<span> + 1 </span>-<span> 1 = 4 </span>-<span> 1</span>Now simplifying both sides we have:x<span> + 0  = 3</span>So:</span><span>x<span>  = 3</span></span></span><span>With some practice you will easily recognise what operations are required to solve an equation.Here are possible ways of solving a variety of linear equation types.<span>Example 1, Solve for ‘x’ :</span>x<span> + 1  =   </span>-31. Subtract 1 from both sides:x<span> + 1 </span>-<span> 1 =   </span>-<span>3 </span>-<span> 1</span>2. Simplify both sides:x<span>   =   </span>-4<span>Example 2, Solve for ‘x’ :</span>-<span>2x   =   12</span>1. Divide both sides by -2:2. Simplify both sides:x<span>   =   </span>-6<span>Example 3, Solve for ‘x’ :</span>1. Multiply both sides by 3:2. Simplify both sides:<span>x   =   </span>-6<span>Example 4, Solve for ‘x’ :</span><span>2x + 1  =  </span>-171. Subtract 1 from both sides:<span>2x + 1 </span>-<span> 1  =  </span>-<span>17 </span>-<span> 1</span>2. Simplify both sides:<span>2x  =  </span>-183. Divide both sides by 2:4. Simplify both sides:<span>x   =   </span>-9<span>Example 5, Solve for ‘x’ :</span>1. Multiply both sides by 9:2. Simplify both sides:<span>3x   =   36</span>3. Divide both sides by 3:4. Simplify both sides:x   =   12<span>Example 6, Solve for ‘x’ :</span>  1. Multiply both sides by 3:  2. Simplify both sides:<span> x + 1   =   21</span>  3. Subtract 1 from both sides:<span> x + 1 </span>-<span> 1 =   21 </span>-<span> 1</span>  4. Simplify both sides:x   =   20<span>Example 7, Solve for ‘x’ :</span><span>7(x </span>-<span> 1)  =  21</span>1. Divide both sides by 7:2. Simplify both sides:<span>x </span>-<span> 1   =   3</span>3. Add 1 to both sides:<span>x </span>-<span> 1 + 1 =   3 + 1</span>4. Simplify both sides:x   =   4<span>Example 8, Solve for ‘x’ :</span>1. Multiply both sides by 5:2. Simplify both sides:<span>3(x </span>-<span> 1)   =   30</span>3. Divide both sides by 3:4. Simplify both sides:<span>x </span>-<span> 1   =   10</span>5. Add 1 to both sides:<span>x </span>-<span> 1 + 1 =   10 + 1</span>6. Simplify both sides:x<span>   =   11</span><span>Example 9, Solve for ‘x’ :</span><span>5x + 2  =  2x + 17</span>1. Subtract 2x from both sides:<span>5x + 2 </span>-<span> 2x =   2x + 17 </span>-<span> 2x</span>2. Simplify both sides:<span>3x + 2   =   17</span>3. Subtract 2 from both sides:<span>3x + 2 </span>-<span> 2 =   17 </span>-<span> 2</span>4. Simplify both sides:<span>3x   =   15</span>5. Divide both sides by 3:6. Simplify both sides:x   =   5<span>Example 10, Solve for ‘x’ :</span><span>5(x </span>-<span> 4)  =  3x + 2</span>1. Expand brackets:<span>5x </span>-<span> 20   =   3x + 2</span>2. Subtract 3x from both sides:<span>5x </span>-<span> 20 </span>-<span> 3x =   3x + 2 </span>-<span> 3x</span>3. Simplify both sides:<span>2x </span>-<span> 20   =   2</span>4. Add 20 to both sides:<span>2x </span>-<span> 20 + 20 =   2 + 20</span>5. Simplify both sides:<span>2x   =   22</span>6. Divide both sides by 2:7. Simplify both sides:x   <span>=   11</span></span>
6 0
3 years ago
Read 2 more answers
Let x = 2 + 8i and xy = –2 + 26i. What is y?<br><br> Answer: 3+i
nekit [7.7K]

Answer:

3+i

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Which fraction is equivalent to 2/7
Snezhnost [94]
4/14, you multiply any number by the numerator and the denominator (make sure it is the same number) and then you have a equivalent fraction! Hope I helped! Have a great day!

5 0
3 years ago
Read 2 more answers
Mindy's dog, Rex, weighed 80 pounds a year ago. Now he weighs 92 pounds. What is the percent increase in his weight?
nadya68 [22]

Answer:

15%

Step-by-step explanation:

To find the percent increase, use the equation:

percent of increase=<u>amount of increase</u>

                                     original amount

The amount of increase is 92-80 = 12.  The original amount of 80; this gives us

12/80 = 0.15 = 15%

5 0
3 years ago
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