Answer:
69.01 m
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you ...
Tan = Opposite/Adjacent
The tangent function is useful for problems like this. Let the height of the spire be represented by h. The distance (d) across the plaza from the first surveyor satisfies the relation ...
tan(50°) = (h -1.65)/d
Rearranging to solve for d, we have ...
d = (h -1.65)/tan(50°)
The distance across the plaza from the second surveyor satisfies the relation ...
tan(30°) = (101.65 -h)/d
Rearranging this, we have ...
d = (101.65 -h)/tan(30°)
Equating these expressions for d, we can solve for h.
(h -1.65)/tan(50°) = (101.65 -h)/tan(30°)
h(1/tan(50°) +1/tan(30°)) = 101.65/tan(30°) +1.65/tan(50°)
We can divide by the coefficient of h and simplify to get ...
h = (101.65·tan(50°) +1.65·tan(30°))/(tan(30°) +tan(50°))
h ≈ 69.0148 ≈ 69.01 . . . . meters
The tip of the spire is 69.01 m above the plaza.
Answer:
<h2>X = 31°</h2>
Step-by-step explanation:
Given: AC is angle bisector of <BAD.
=> So, <BAC = <CAD
30° = x-1 °
30 +1 = x
31 = x
Then,<u> X = 31</u>
<em>Hope</em><em> </em><em>this helps</em><em>.</em><em>.</em><em> </em><em>Good</em><em> </em><em>luck</em><em> </em><em>:</em><em>)</em><em> </em>
The answer is: The second one. Why?
Because, when it's a linear graph, the slope of the graph cannot change.
And that's the only graph that fits the criteria
Hope this helped! c:
Answer:
x+27
Step-by-step explanation:
Let's simplify step-by-step.
4(x+3)+3(5−x)
Distribute:
=(4)(x)+(4)(3)+(3)(5)+(3)(−x)
=4x+12+15+−3x
Combine Like Terms:
=4x+12+15+−3x
=(4x+−3x)+(12+15)
=x+27
Hope you find this Useful!
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
