So we are given the expression:
÷ 
When we divide fractions, we must flip the second term and change the sign to multiplication:

And then we multiply across:

Then we can break apart all of the like variables for simplification:

When we simplify variables through division, we subtract the exponent of the numerator from the exponent of the denominator. So we then have:



So then we multiply all of these simplified parts together:

So now we know that the simplified form of the initial expression is:
.
54+x=12+3x
X=21 =number of classes
Total amount she will pay is $75
#1) A
#2) E
#3) C
#4) 0.5840
#5) 0.6945
#6) 0.4911
#7) D
#8) G
#9) 0.4375
#10) 0.5203
The formula we use for this is

,
where

is the speed of sound, f is the frequency (or pitch) of the note, and λ is the wavelength.
#1) 0.77955f = 343
Divide both sides by 0.77955:
0.77955f/0.77955 = 343/0.77955
f = 439.997 ≈ 440. This is the pitch for A.
#2) 0.52028f = 343
Divide both sides by 0.52028, and we get f = 659.260. This is the pitch for E.
#3) 0.65552f = 343
Divide both sides by 0.65552, and we get f = 523.25. This is the pitch for C.
#4) 587.33λ = 343
Divide both sides by 587.33 and we get λ = 0.583999 ≈ 0.5840.
#5) 493.88λ = 343
Divide both sides by 493.88, and we get λ = 0.6945.
#6) 698.46λ = 343
Divide both sides by 698.46 and we get λ = 0.49108 ≈ 0.4911.
#7) 0.5840f = 343
Divide both sides by 0.5840 and we get f = 587.3288 ≈ 587.33. This is the pitch for D.
#8) 0.4375f = 343
Divide both sides by 0.4375 and we get f = 784. This is the pitch for G.
#9) 783.99λ = 343
Divide both sides by 783.99 and we get λ = 0.4375.
#10) 659.26λ = 343
Divide both sides by 659.26 and we get λ = 0.52028 ≈ 0.5203.
Answer:
10 square inches per second.
Step-by-step explanation:
The radius of the circle is given by the equation:
r(t) = (1/π in/s)*t
Where time in seconds.
Remember that the area of a circle of radius R is written as:
A = π*R^2
Then the area of our circle will be:
A(t) = π*( (1/π in/s)*t)^2 = π*(1/π in/s)^2*(t)^2
Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.
Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.
r(t) = 5 in = (1/ in/s)*t
5in*(π s/in) = t
5*π s = t
So the radius will be equal to 5 inches after 5*π seconds, let's remember that.
Now let's find the first derivate of A(t)
dA(t)/dt = A'(t) = 2*(π*(1/π in/s)^2*t = (2*π*t)*(1/π in/s)^2
Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:
A'(5*π s) = (2*π*5*π s)*((1/π in/s)^2
= (10*π^2 s)*(1/π^2 in^2/s^2) = 10 in^2/s
The rate of change is 10 square inches per second.
<span>The answer is D. Distributive
It is a distributive problem because you are are distributing the numbers within the parenthesis.
Hope this helped. Have a great day!</span>