The product two consecutive odd numbers is 63find the number

Mathematics

1 answer:

anygoal [31]2 years ago

7 0

Answer:

These results, 7 and 9, have a product of 63, as stated.

Step-by-step explanation:

Represent the first odd number by x and the first consecutive odd number by x + 2. Then the product of these two numbers is x(x + 2) and it equals 63.

Solve for x. Perform the indicated multiplication, obtaining

x^2 + 2x - 63 = 0

Solve this by factoring: (x + 9)(x - 7) = 0

Then x could be either -9 or +7. If we let x = 7 then the first consecutive odd number is 7 + 2, or 9. These results, 7 and 9, have a product of 63, as stated.

You might be interested in

What is the measure of arc WYZ? ---------- 231 255 200 168

Nataly_w [17]

9514 1404 393

Answer:

(a) 231°

Step-by-step explanation:

arc WYZ = arc WX + arc XYZ

arc WYZ = 51° +180° . . . . . XZ is a diameter, substitute known arc measures

arc WYZ = 231°

7 0

2 years ago

Give an example of an integer and its opposite. step by step answer please no downloads

UkoKoshka [18]

Answer:

integer: -2 opposite: 2

Step-by-step explanation:

the opposite of an integer is just the positive form of the negative-1,1. -3 3 etc

8 0

3 years ago

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500