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babymother [125]
3 years ago
7

What is the answer x^2+28=0

Mathematics
2 answers:
marshall27 [118]3 years ago
5 0

Answer:

the answer is ( there is no real solutions) i hoped this help if you need an explanation why let me know :)

Blababa [14]3 years ago
3 0

Answer:

x = 2√7 or 5.2915

Step-by-step explanation:

x^2 + 28 = 0

first get the variable by itself by subtracting the 28 from both sides. 28-28 cancels and 0-28=-28.

now you have

x^2 = -28

take the square root of x^2 to cancel out the exponent, and then do the same to the other side,

x = √28

x = 2√7 or 5.2915

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Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

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\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

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Substitute, we get,

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Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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hope this helps ;) xx

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