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babymother [125]
3 years ago
7

What is the answer x^2+28=0

Mathematics
2 answers:
marshall27 [118]3 years ago
5 0

Answer:

the answer is ( there is no real solutions) i hoped this help if you need an explanation why let me know :)

Blababa [14]3 years ago
3 0

Answer:

x = 2√7 or 5.2915

Step-by-step explanation:

x^2 + 28 = 0

first get the variable by itself by subtracting the 28 from both sides. 28-28 cancels and 0-28=-28.

now you have

x^2 = -28

take the square root of x^2 to cancel out the exponent, and then do the same to the other side,

x = √28

x = 2√7 or 5.2915

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If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i
nadya68 [22]

Answer:

  • 12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

  • 28 - 4 = 24
  • 39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

  • 24 = 2*2*2*3
  • 36 = 2*2*3*3
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The largest possible number of students is 12

7 0
3 years ago
What is another way to write the expression? t. (14-5)
Kazeer [188]
Hope this is what you where looking for

5 0
3 years ago
The commute time to work in the U.S. Has a bell shaped distribution with a population mean of 24.4 minutes and a population stan
Alexxx [7]

Answer:

1. 0.9544

2. 0.0228

3. 0.0228

Step-by-step explanation:

The computation is shown below;

As we know that

At Normal distribution

P(X < A) = P(Z < \frac{(A - mean)}{standard deviation})

As per the question, the data provided is as follows

Mean = 24.4 minutes

Standard deviation = 6.5 minutes

Based on the above information

P(11.4 < X < 37.4) = P(X < 37.4) - P(X < 11.4)

= P(Z < (37.4 - 24.4) ÷ 6.5) - P(Z < (11.4 - 24.4) ÷ 6.5)

= P(Z < 2) - P(Z < -2)

= 0.9772 - 0.0228

= 0.9544

2. P(X < 11.4) = 0.0228

3. P(X ≥ 37.4) = 1 - P(X < 37.4)

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5 0
4 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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