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iren [92.7K]
3 years ago
8

Does the relationship in this table represent a proportional relationship? x 0.25 0.5 0.6 1.75 y 3.25 3.5 3.6 4.75 Select from t

he drop-down menu to correctly complete the statement The relationship Choose v represent a proportional relationship? drop down menu- does, does not​
Mathematics
2 answers:
atroni [7]3 years ago
6 0

Answer:yes it does

Step-by-step explanation:

ioda3 years ago
4 0

Answer:

yes it does I had this question

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The new number, 200, is 400 less than the original number. What is the approximate percent change?
wolverine [178]
The percent change is approximately 66%
8 0
3 years ago
Read 2 more answers
a rectangular room is 7 feet wide. it is twice as long as it is wide. what is the perimeter of the room?
Fiesta28 [93]
42 because it is all of the sides have to be added up for the perimeter so the formula would be 14+14+7+7.

4 0
4 years ago
Find the values of x and y in the diagram.
brilliants [131]

Answer:

x = 2, y = 6

Step-by-step explanation:

Δ WXY is equilateral ( 3 congruent angles ), then the sides are equal

WY = WX , that is

y - 1 = 5 ( add 1 to both sides )

y = 6

Δ WYZ is isosceles ( 2 congruent base angles ) then the legs are congruent

YZ = WY , that is

x + 3 = 5 ( subtract 3 from both sides )

x = 2

7 0
3 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
4 years ago
Helpppp pleaseeee , thank you .
34kurt

Answer:

20 yds

Step-by-step explanation:

4 0
4 years ago
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