Velocity is define as the time rate taken for a change in acceleration
Answer:
The force of friction that acts on him is

Explanation:
The firefighter with an acceleration of 3m/s^2 take the gravity acceleration as 10m/s^2 isn't necessary to know the coefficient of friction just to know the force of friction:




Sole to Fk



Answer:
Terminal speed, v = 6901.07 m/s
Explanation:
It is given that,
Mass of the horizontal bar, m = 30 g = 0.03 kg
Length of the bar, l = 13 cm = 0.13 m
Magnetic field, 
Resistance, R = 1.2 ohms
We need to find the terminal speed oat which the bar falls. When terminal speed is reached,
Force of gravity = magnetic force
..................(1)
i is the current flowing
l is the length of the rod
Due to the motion in rods, an emf is induced in the coil which is given by :
, v is the speed of the bar


Equation (1) becomes,



v = 6901.07 m/s
So, the terminal speed at which the bar falls is 6901.07 m/s. Hence, this is the required solution.
Answer:
magnitude is 1382.59 N/C
Explanation:
Given the data in the question;
The time taken is;
t = x / v
we substitute;
t = ( 2 × 10⁻²) / ( 5.69 × 10⁶ )
t = 3.5149 × 10⁻⁹ s
next, the acceleration is;
a = 2y/t² = [2( 0.150 × 10⁻²)] / [ ( 3.5149 × 10⁻⁹ )² ]
a = 2.42826 × 10¹⁴ m/s²
now, the electric field is;
E = ma / q
we know that;
mass of electron m = 9.11 × 10⁻³¹ kg,
charge of electron q = 1.60 × 10⁻¹⁹ coulomb
we substitute
E = ( 9.11 × 10⁻³¹ )(2.42826 × 10¹⁴) / 1.60 × 10⁻¹⁹
E = 2.21214 × 10⁻¹⁶ / 1.60 × 10⁻¹⁹
E = 1.3826 × 10²¹
E = 1382.59 N/C
Therefore, magnitude is 1382.59 N/C
Explanation:
KE =1/2 MV^2
HOPE YOU COULD SOLVE FROM NOW..