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Dmitry_Shevchenko [17]
2 years ago
14

A 35 kg object has -450 kgm/s of momentum. Calculate its velocity.

Physics
1 answer:
shtirl [24]2 years ago
7 0

Hi there!

Recall the equation for momentum:

\large\boxed{p = mv}\\

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

We can plug in the given values to solve for velocity:

-450 = 35v\\\\v = \frac{-450}{35} = \boxed{12.86 m/s}

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According to Charles' law, as the temperature of a given gas at constant pressure is increased, the volume will also
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3 years ago
A square loop of wire is held in a uniform 0.24 T magnetic field directed perpendicular to the plane of the loop. The length of
NNADVOKAT [17]

Answer:

Explanation:

Given that,

Magnetic field of 0.24T

B = 0.24T

Field perpendicular to plane i.e 90°

Rate of decrease of length of side of square is 5.4cm/s

dL/dt = 5.4cm/s = 0.054m/s

Since it is decreasing

Then, dL/dt = -0.054m/s

When L is 14cm, what is the EMF induced?

L = 14cm = 0.14m

EMF is give as

ε = - dΦ/dt

Where flux is given as

Φ = BA

Where A is the area of the square

A = L²

Then, Φ = BL²

Substituting this into the EMF

ε = - dΦ/dt

ε = - d(BL²)/dt

B is constant

ε = - Bd(L²)/dt

ε = -2BL dL/dr

ε = -2 × 0.24 × 0.14 × -0.054

ε = 3.63 × 10^-3 V

ε = 3.63mV

8 0
4 years ago
After polishing his 2-kg wrestling trophy, Mike sets it down on the ground and walks away to find more polish. Meanwhile, Julie
klio [65]

1) The initial momentum of the trophy is zero

2) The initial momentum of the bowling ball is 160 kg m/s

3) The total momentum before the collision is 160 kg m/s

4) The total momentum of the system after the collision is 160 kg m/s

5) The final velocity of the trophy is 32 m/s

Explanation:

1)

The momentum of an object is given by

p=mv

where

m is the mass of the object

v is its velocity

In this problem, the data for the trophy before the collision are:

m = 2 kg is the mass

v = 0 is its initial velocity

Therefore, the initial momentum of the trophy is

p_1=(2)(0)=0

2)

Using the same equation used in part 1), the initial momentum of the bowling ball is

p=mv

where

m is the mass of the bowling ball

v is its initial velocity

The data of the problem are

m = 8 kg is the mass

v = 20 m/s is the velocity

Substituting,

p_2=(8)(20)=160 kg m/s

3)

The total momentum of the system before the collision is given by the sum between the initial momentum of the trophy and the initial momentum of the bowling ball:

p_i = p_1 + p_2

where

p_1 is the initial momentum of the trophy

p_2 is the initial momentum of the ball

Here we have

p_1 = 0

p_2 = 160 kg m/s

Therefore, the total momentum is

p_i = 0 + 160 = 160 kg m/s

4)

According to the law of conservation of momentum, for an isolated system (=no external unbalanced forces acting on the system), the total momentum of the system is conserved before and after the collision:

p_i = p_f

where

p_i is the total momentum before the collision

p_f is the total momentum after the collision

If we consider the system in the problem to be isolated (i.e. no frictional forces acting on the ball or the trophy), we can therefore say that the total momentum after the collision must be equal to the total momentum before the collision: therefore,

p_f = 160 kg m/s

5)

We can write the total momentum after the collision as

p_f = m_1 v_1 + m_2 v_2

where:

m_1 = 2 kg is the mass of the trophy

v_1 is the final velocity of the trophy

m_2 = 8 kg is the mass of the bowling ball

v_2 = 12 m/s is the final velocity of the ball

Since we also know the value of the final total momentum,

p_f = 160 kg m/s

we can solve the equation to find the velocity of the trophy:

v_1 = \frac{p_f - m_2 v_2 }{m_1}=\frac{160-(8)(12)}{2}=32 m/s

Learn more about momentum:

brainly.com/question/7973509

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#LearnwithBrainly

4 0
3 years ago
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