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Dmitry_Shevchenko [17]
2 years ago
14

A 35 kg object has -450 kgm/s of momentum. Calculate its velocity.

Physics
1 answer:
shtirl [24]2 years ago
7 0

Hi there!

Recall the equation for momentum:

\large\boxed{p = mv}\\

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

We can plug in the given values to solve for velocity:

-450 = 35v\\\\v = \frac{-450}{35} = \boxed{12.86 m/s}

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A 5.0-ohm resistor, a 10.0-ohm resistor, and a 15.0-ohm resistor are connected in parallel with a battery. The current through t
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Answer:

E = 3456 J

Explanation:

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E = Energy Expended = ?

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8 0
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A student throws a rock horizontally from the edge of a cliff that is 20 m high. The rock has an initial speed on 10 m/s. If air
fiasKO [112]

The distance of the rock from the base of the cliff is C) 20 m

Explanation:

The motion of the rock in this problem is a projectile motion, which consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction

We start by analyzing the vertical motion to find the time of flight of the rock (the time it takes to reach the ground). We can do it by using the suvat equation:

s=u_y t+\frac{1}{2}at^2

where, taking downward as positive direction,

s = 20 m is the vertical displacement of the rock

u_y=0 is the initial vertical velocity

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Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(20)}{9.8}}=2.02 s

Now we can analzye the horizontal motion: the rock moves horizontally with a constant velocity of

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Therefore, the horizontal distance covered after a time t is

d=v_x t

and substituting t = 2.02 s, we find the final distance of the rock from the base of the cliff:

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Learn more about projectile motion:

brainly.com/question/8751410

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