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2 years ago

a rental car agency charges 190 per a week plus .25 per mile to rent a car. How many miles can you travel in one week for 370

Mathematics

1 answer:

alekssr [168]2 years ago

8 0

Let m represent the number of miles traveled. If the whole budget amount of 370 is spent, then ...

... 190 + 0.25m = 370

... 0.25m = 280

... m = 280/0.25 = 1120

For 370, you can travel 1120 miles.

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Andrea is at the grocery store buying fruit for a smoothie stand. She needs 7 boxes of raspberries for every 5 bunches of banana

Degger [83]

Answer:

The greatest number of bunches of bananas that Andrea can buy is 15 and the greatest number of boxes of raspberries that Andrea can buy is 21 to maintain the ratio 7:5

Step-by-step explanation:

Let

x ---->the greatest number of boxes of raspberries that Andrea can buy

y ---->the greatest number of bunches of bananas that Andrea can buy

we know that

$100\%+8\%=106\%=108/100=1.08$ ---> sales tax

$\frac{x}{y} =\frac{7}{5}$

$x=\frac{7}{5}y$ ----> equation A

$1.08[2.50x+3.00y]\leq 135$ ----> inequality B

substitute equation A in the inequality B

$1.08[2.50(\frac{7}{5}y)+3.00y]\leq 135$

solve for y

Multiply by 5 both sides to remove the fraction

$18.9y+16.2y\leq 675$

$35.1y\leq 675$

$y\leq 19.23$

The maximum value of y is 19

Find the value of x

replace the value of y in equation A until you get an integer value that satisfies the ratio 7:5

For y=19

$x=\frac{7}{5}(19)$

$x=26.6$

For y=18

$x=\frac{7}{5}(18)$

$x=25.2$

For y=17

$x=\frac{7}{5}(17)$

$x=23.8$

For y=16

$x=\frac{7}{5}(16)$

$x=22.4$

For y=15

$x=\frac{7}{5}(15)$

$x=21$

therefore

The greatest number of of bunches of bananas that Andrea can buy is 15 and the greatest number of boxes of raspberries that Andrea can buy is 21 to maintain the ratio 7:5

<u><em>Verify the inequality B</em></u>

$1.08[2.50(21)+3.00(15)]\leq 135$

$1.08[52.5+45]\leq 135$

$105.3\leq 135$ ----> is true

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