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2 years ago

Find x and y please

Mathematics

2 answers:

Alexandra [31]2 years ago

6 0

Answer:

Answer:

x → 4.24
y → 4.24

Step-by-step explanation:

» x and y can only be got through using trigonometric ratios:

✍ For x :

${ \tt{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ \\ { \tt{ \sin(45 \degree) = \frac{x}{6} }} \\ \\ { \tt{x = 6 \times \sin(45 \degree) }} \\ { \tt{x = 4.24}}$

✍ For y :

${ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( 45 \degree) = \frac{y}{6} }} \\ \\ { \tt{y = 6 \times \cos(45 \degree) }} \\ { \tt{y = 4.24}}$

natulia [17]2 years ago

5 0

Answer:

see below

Step-by-step explanation:

this is a 45 90 45-45-90 right triangle. the side is x and the hypotenuse is x*(sqrt(2)). the hypotenuse is 6, so the side is 3(sqrt(2)).

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What is a rule for the nth term of the sequence 1/2, 1/4, 1/6, 1/8, ...?

rewona [7]

Answer:

1/18

Step-by-step explanation:

the denominator is going up by 2s

pls brainliest

4 0

2 years ago

Read 2 more answers

10. 9. Solve the equation (x-2)(x+2) = 0 (4F) A. 02,0 B. O-2, 2 C.O-2 D. 2

masha68 [24]

Answer:

x=2 or x=-2

Step-by-step explanation:

I'm not sure what you're asking, but when you solve, set both sets of parentheses equal to 0 and solve. This makes x either equal to 2 or -2.

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3 years ago

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$

$\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

The domain of definition of F is

$\large \mathbb{R}^2-\{(0,0)\}$

i.e., all the plane X-Y except the (0,0)

Here we want to find all the points such that

$\large (-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})=(k,k)$

where k is a real number other than 0.

But this means

$\large -\frac{y}{x^2+y^2}=\frac{x}{x^2+y^2}\Rightarrow y=-x$

So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0

8 0

2 years ago

How do you find the value of X

deff fn [24]

Answer:

look at the angles. they all ad up to 180 degrees devide that by 9, and there you go!

Step-by-step explanation:

7 0

3 years ago

From given figure write the radiation between m and n.

Ulleksa [173]

Answer:

see explanation

Step-by-step explanation:

m and n are same- side interior angles and sum to 180°

6 0

2 years ago