Answer:
There are two rational roots for f(x)
Step-by-step explanation:
We are given a function

To find the number of rational roots for f(x).
Let us use remainder theorem that when
f(a) =0, (x-a) is a factor of f(x) or x=a is one solution.
Substitute 1 for x
f(1) = 1-2-5+6=0
Hence x=1 is one solution.
Let us try x=-1
f(-1) = 1-2-5+6 =0
So x =-1 is also a solution and x+1 is a factor
We can write f(x) by trial and error as

We find that
factor gives two irrational solutions as
±√3.
Hence number of rational roots are 2.
Answer:
1. 4/7 = 16/28
Check:
(4/7)(4/4) = 16/28 = 16/28
2. 40/15 = 8/3
Check:
(40/15)/(5/5) = 8/3
3. 15/6 = 5/2
Check:
(15/6)/(3/3) = 5/2
4. 8/11 = 56/77
Check:
(8/11)(7/7) = 56/77
5. 9/2 = 63/14
Check:
(9/2)(7/7) = 63/14
~
Answer:
0.625 s
Step-by-step explanation:
5s/8
0.625 s
1) 1/7
2) 1/2
3) 1/9
4) 1/4
5) 1/3
6) 2/15
hope this helped:)
5/40 = 1/8 so your taking it and dividing by 5