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3 years ago

What is the GCF of x^6 and x^5

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

5 0

Hi im Aleida and go to calculatorsoup on Safari or google and put gcf calculatorsoup hope this helps

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What is the rate of change of the line

butalik [34]

B 5 feet per second

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3 years ago

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23 is the quotient of a number t and 61

Sever21 [200]

Answer:

Mao ni ang answer

$61 \div 23 = 1$

Thx sa points

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3 years ago

Which number is an integer? A: -9,248.3 B: -16/17 C: 10,839 D: 35,749.087

tatiyna

The correct answer is c!

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3 years ago

E-4 - 5 - 6 - → The perimeter of a rectangle is 425 yards. The length and width of the rectangle are each multiplied by 6. What

Alex73 [517]

Answer:

2550yards

Step-by-step explanation:

Perimeter of a rectangle = 2L + 2W

L is the length

W is the width

If perimeter of a rectangle is 425 yards, then;

425 = 2L + 2W

425 = 2(L+W)

L+W = 425/2 .... 1

If the length and width of the rectangle are each multiplied by 6

P = 6(2L) + 2(2W)

P = 12L + 12W

P = 12(L+W) .... 2

Substitute 1 into 2

P = 12(425/2)

P = 6*425

P = 2550yd

Hence the perimeter of new triangle is 2550yards

4 0

3 years ago

Read 2 more answers

First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia

RUDIKE [14]

Answer:

3.728 cm²

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is $28 \times \frac{1}{12} = 2.33$ m and the width of the patches is $12 \times \frac{2}{15} = 1.6$ m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, $\frac{336}{3.728} = 90.37$ ≈ 90 such patches can be made out of the whole material. (Answer)

3 0

3 years ago