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2 years ago

Two star systems are part of a ________________ system formation.

Chemistry

1 answer:

Radda [10]2 years ago

5 0

Binary Stars I think

hope this is right and helps

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G x mol/g x atoms/mol= <br><br> what are the units remaining after conversion

antiseptic1488 [7]

Answer:

The "unit" remaining after conversion is atoms.

This is a way to calculate the number of atoms, in an specific mass.

Explanation:

When you have a mass, multiplying the molar mass, "grams" are cancelled, so you finally obtained, number of moles.

Moles . atoms/mol, cancel the word mol so you will find out a number of atoms, present at the mass from, the begining.

For example, how many atoms are in 10 g of NaCl

Molar mass NaCl = Na mass + Cl mass

23 + 35.45 = 58.45 g/m

10 g . 1 / 58.45 mol/g . NA/ 1 mol = 3.42x10²⁰ atoms

NA = Avogadro number

3 0

4 years ago

Tameca is planning a hiking trip. The trail she would like to follow is 7.5 miles long. She plans to start her hike at 10:00 am.

V125BC [204]

Answer:

1.5 miles per hour

Explanation:

7.5 miles in 5 hours

7.5/5=1.5 miles per hour

6 0

3 years ago

What is the conversion for mass

elena55 [62]

neither created nor destroyed in chemical reactions. In other words, themass of any one element at the beginning of a reaction will equal the mass<span> of that element at the end of the reaction.</span>

6 0

3 years ago

12 is produced by the reaction of 0.5235 mol of CuCl2 according to the following equation: 2CuCl2 +4K1—2Cul + 4KCI + 12. What is

Keith_Richards [23]

Answer:

The mass of I₂ produced is 66.43 g.

Explanation:

In a stoichiometry exercise we follow a series of steps.

Step 1: Write the balanced equation

2 CuCl₂ + 4 KI ⇄ 2 CuI + 4 KCl + I₂

Step 2: Look for the relationship between the data we have and the one we are looking for

According to the balanced equation, when 2 moles of CuCl₂ react 1 mole of I₂ is formed. This is the first relation. Secondly, we know that the molar mass of 253.80 g/mol, that is, every mole of I₂ has a mass of 253.80 g. This is the second relation.

Step 3: Apply relations to the data we have

$0.5235mol(CuCl_{2}).\frac{1mol(I_{2})}{2mol(CuCl_{2})} .\frac{253.80g(I_{2})}{1mol(I_{2})} =66.43g(I_{2})$

7 0

3 years ago

You and your science group have been handed five mineral samples to identify. First, you sort the minerals by color. One has man

coldgirl [10]

im pretty sure it is b

tghj

6 0

3 years ago