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navik [9.2K]
3 years ago
8

ASAP (:

Chemistry
1 answer:
Korvikt [17]3 years ago
5 0

1) CO (g) + 2H_{2}(g) ---> CH_{3}OH (g)

Moles of methanol = 208 kg CH_{3}OH * \frac{1000 g}{1 kg} * \frac{1 mol CH_{3}OH}{32.04 g CH_{3}OH} = 6492 mol CH_{3}OH

Mass of H_{2} that would produce 208 kg methanol =

6492 mol CH_{3}OH * \frac{2 mol H_{2}}{1 mol CH_{3}OH} * \frac{2.02 g H_{2}}{1 mol H_{2}} * \frac{1 kg}{1000 g}=  26.2 kg H_{2}

2) Mass of sodium = 1.3 * 10^{21} atoms Na * \frac{1 mol Na}{6.022* 10^{23}atoms Na} * \frac{22.99 g Na}{1 mol Na} = 0.0496 g Na

3) Mass of mercury = 1.2 mL * 13.6 \frac{g}{mL} = 16.32 g

Number of atoms of mercury = 16.32 g Hg * \frac{1 mol Hg}{200.59 g Hg} * \frac{6.022* 10^{23} atoms Hg}{1 mol Hg} =   4.9 * 10^{22} atoms Hg

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To calculate the number of moles of gas remaining in his after he exhale, we'll have to use Avogadro's law which states that the volume of a given mass of gas is directly proportional to its number of moles provided that temperature and pressure are kept constant. Mathematically,

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