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navik [9.2K]
4 years ago
8

ASAP (:

Chemistry
1 answer:
Korvikt [17]4 years ago
5 0

1) CO (g) + 2H_{2}(g) ---> CH_{3}OH (g)

Moles of methanol = 208 kg CH_{3}OH * \frac{1000 g}{1 kg} * \frac{1 mol CH_{3}OH}{32.04 g CH_{3}OH} = 6492 mol CH_{3}OH

Mass of H_{2} that would produce 208 kg methanol =

6492 mol CH_{3}OH * \frac{2 mol H_{2}}{1 mol CH_{3}OH} * \frac{2.02 g H_{2}}{1 mol H_{2}} * \frac{1 kg}{1000 g}=  26.2 kg H_{2}

2) Mass of sodium = 1.3 * 10^{21} atoms Na * \frac{1 mol Na}{6.022* 10^{23}atoms Na} * \frac{22.99 g Na}{1 mol Na} = 0.0496 g Na

3) Mass of mercury = 1.2 mL * 13.6 \frac{g}{mL} = 16.32 g

Number of atoms of mercury = 16.32 g Hg * \frac{1 mol Hg}{200.59 g Hg} * \frac{6.022* 10^{23} atoms Hg}{1 mol Hg} =   4.9 * 10^{22} atoms Hg

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How can you calculate the energy of an electron who moved from E1 to E5?
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Answer:

See explanation

Explanation:

If the energy of the ground state E1 is known, then we need to measure the difference in energy between the energy levels E5 .and E1. We can obtain this by measuring the frequency or wavelength of a photon that is emitted when an electron moves from energy level E5 to E1.

From Bohr's model;

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For the reaction Fe3O4(s) + 4H2(g) --> 3Fe(s) + 4H2O(g)
mojhsa [17]

Answer : The value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

Explanation :

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy  = ?

\Delta H^o = standard enthalpy = 151.2 kJ = 151200 J

\Delta S^o = standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

\Delta G^o=(151200J)-(328.0K\times 169.4J/K)

\Delta G^o=95636.8J=95.6kJ

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln k

where,

\Delta G^o = standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

95636.8J=-(8.314J/K.mol)\times (328.0K)\times \ln k

k=1.70\times 10^{15}

Therefore, the value of equilibrium constant for this reaction at 328.0 K is 1.70\times 10^{15}

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What causes the changes in air pressure on the earth surface
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<span>Atmospheric Pressure</span>
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People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m
Llana [10]

Answer:

V_{HCl}=0.208L=208mL

Explanation:

Hello,

In this case, since the chemical reaction is:

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

n_{HCl}=2*n_{Mg(OH)_2}

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g}  =0.00858mol

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M

Then, since the concentration and the volume define the moles, we can write:

[HCl]*V_{HCl}=2*n_{Mg(OH)_2}

Therefore, the neutralized volume turns out:

V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL

Best regards.

3 0
3 years ago
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