Question

Write an equation of the line that passes through (7,10) and is perpendicular to the line y=1/2x−9.

Answer 1

y = -2x + 24

hope this is helpful!

Answer 2

Answer:

y+2x=24

Step-by-step explanation:

the equation of the line: y=1/2x -9

Get the slope by using derivative:

dy/dx= 1/2

dy/dx= slope of the normal line

Since we are looking for slope of the tangent line:

Use Mn=-1/Mt

The slope of the tangent line is -2

Using point slope form:

(y-y1)=m(x-x1) ; where x1=7, y1=10, and m=-2

y-10=-2(x-7)

y-10=-2x+14

ANSWER: y+2x=24