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3 years ago

Q.The total surface area of a cylinder is

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

Answer:

r≈14cm

h Height

A Surface area

3080

cm²

Using the formula

A=2πrh+2πr2

Solving forr

r=1

2h2+2A

π﹣h

2=1

2·212+2·3080

π﹣21

2≈14.00402cm

You might be interested in

Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f

tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :- f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x) to have a maximum or minimum at given point.

ii) find first derivative $f^{l} (x)$ and equating zero

iii) solve and find 'x' values

iv) Find second derivative $f^{ll}(x) >0$ then find the minimum value at x=a

v) Find second derivative $f^{ll}(x)$ then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative $f^{l} (x)$ and equating zero

$f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)$

$f^{l}(x) = \frac{1}{x^2+1} (2x)$ ……………(1)

$f^{l}(x) = \frac{1}{x^2+1} (2x)=0$

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

$f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}$

on simplification , we get

$f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}$

put x= 0 we get $f^{ll}(0) = \frac{2}{(1)^2}$ > 0

$f^{ll}(x) >0$ then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0

4 years ago

NEED HELP ASAP!! WILL MARK BRAINLIEST TO THE RIGHT ANSWER!!

Usimov [2.4K]

For the first one :) x + 6, y - 10

6 0

3 years ago

Please answer Correctly for brainly

lorasvet [3.4K]

C is FALSE

the set of whole numbers is { 0, 1, 2, 3, 4 , ......}

the set of integers is { ..., - 2, - 1, 0, 1, 2, 3, ......}

As we can see the set of whole numbers does not include negative numbers, thus integers are not a subset of whole numbers

However, whole numbers are a subset of integers.

8 0

4 years ago

Factoring a quadratic with leading coefficient greater than 1 <br><br> 3n^2+5n+2=0

Alika [10]

The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0.

<h3>What is an algebraic factor?</h3>

An algebraic factor is the multiplication of two algebraic terms.

The root of the quadratic equation formed by the algebraic factor is always real.

That term could be in form of summation multiplication or in subtraction.

As per the given quadratic equation,

3n²+5n+2=0

Let's 5n = 2n + 3n

3n²+ (3n + 2n) + 2 = 0

3n² + 3n + 2n + 2 = 0

(3n² + 3n) + (2n + 2) = 0

3n(n + 1) + 2(n + 1) = 0

(n + 1 )(3n + 2) = 0

Hence "The algebraic factor is the multiplication term that can be common to the whole equation thus the factorization form of 3n²+5n+2=0 will be (n + 1)(3n + 2) = 0".

For more about the algebraic factor,

brainly.com/question/19426180

#SPJ1

8 0

1 year ago

Evaluate the equation 4K-10/k=8

solong [7]

Answer:

k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)

Step-by-step explanation:

Solve for k over the real numbers:

4 k - 10/k = 8

Bring 4 k - 10/k together using the common denominator k:

(2 (2 k^2 - 5))/k = 8

Multiply both sides by k:

2 (2 k^2 - 5) = 8 k

Expand out terms of the left hand side:

4 k^2 - 10 = 8 k

Subtract 8 k from both sides:

4 k^2 - 8 k - 10 = 0

Divide both sides by 4:

k^2 - 2 k - 5/2 = 0

Add 5/2 to both sides:

k^2 - 2 k = 5/2

Add 1 to both sides:

k^2 - 2 k + 1 = 7/2

Write the left hand side as a square:

(k - 1)^2 = 7/2

Take the square root of both sides:

k - 1 = sqrt(7/2) or k - 1 = -sqrt(7/2)

Add 1 to both sides:

k = 1 + sqrt(7/2) or k - 1 = -sqrt(7/2)

Add 1 to both sides:

Answer: k = 1 + sqrt(7/2) or k = 1 - sqrt(7/2)

4 0

3 years ago