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vredina [299]
3 years ago
11

One number is 3 less than 4 times a second number. The difference of the

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

17 and 5

Step-by-step explanation:

Interesting question!

Turn both sentences to equations:

a=4b-3\\a-2b=7

a is the first number, and b is the second number.

A system of equations! A graphing calculator will do the work:

(See picture)

The y in the picture is a, and the x in the picture is b.

So the solution is a=17 and b=5

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One endpoint (-1,-5) Midpoint (2,3)
Alecsey [184]
I don’t know the answer but I need a answer to this
4 0
3 years ago
Which set of ordered pairs represents a function
11Alexandr11 [23.1K]

Answer:

C: is a function because each input (x) has exactly one output( y).

Step-by-step explanation:

A function is when one input (x) has exactly one output (y).

A: is not a function because -4 is paired with two different y values.

B: is not a function because -4 is paired with two different y values.

C: is a function because each input (x) has exactly one output( y).

D: is not a function because -1 is paired with two different y values.

3 0
2 years ago
What is the lowest value of the range of the function shown on the graph?
insens350 [35]
The complete question in the attached figure

we know that
the range is the y-value  of the function
so
the lowest y-value on this graph is y = -2.

the answer is
y=-2

5 0
3 years ago
Read 2 more answers
Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters. What is the diagonal d
jolli1 [7]

Answer:

70.7 meters.

Step-by-step explanation:

We have been given that Elise walks diagonally from one corner of a square plaza to another. Each side of the plaza is 50 meters.

Since we know that diagonal of a square is product of side length of square and \sqrt{2}. So we will find diagonal of our given square plaza by multiplying 50 by \sqrt{2}.

\text{Diagonal distance across the plaza}=50\times \sqrt{2}

\text{Diagonal distance across the plaza}=50\times 1.414213562373095

\text{Diagonal distance across the plaza}=70.71067811865475\approx 70.7

Therefore, diagonal distance across the plaza is 70.7 meters.


8 0
3 years ago
What is the area of this figure?
Luden [163]

Answer:

The area of this figure is 24mm.

Step-by-step explanation:

4mm*3mm=12mm

1mm*6mm=6mm

3mm*4mm=12mm/2mm=6mm

6mm+6mm+12mm=24mm

3 0
3 years ago
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