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Oksanka [162]
2 years ago
13

Which of these expressions requires a variable?

Mathematics
1 answer:
Tatiana [17]2 years ago
7 0
D. there is no numbers to work with so you just have to use a variable
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George believes the Art Club students at his school have an unfair advantage in being assigned to the art class they request. He
krek1111 [17]

Answer:

I think that they all have fairness in the class assignment process.

I think this because of the way that more people take art club than art class,

Step-by-step explanation:

8 0
3 years ago
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Dilly is 7 years younger than Dally. In 4 years time she will be half Dally’s age. What is the sum of their ages now?
Step2247 [10]

Answer:

<u>The sum of their ages now is 13</u>

Step-by-step explanation:

Dally's age = x

Dilly's age = x - 7

In 4 years time Dilly will be half Dally’s age, therefore:

Dilly's age plus four equals to half of Dally’s age plus four,

replacing with the values and variables we know:

x - 7 + 4 = (x + 4) /2

x - 3 = (x + 4) /2

2x - 6 = x + 4 (Multiplying by 2 at both sides)

2x - x = 4 + 6 (Like terms)

x = 10 ⇒ x - 7 = 3

<u>The sum of their ages now is 13 (10 + 3)</u>

4 0
3 years ago
What is the solution to Negative 1 minus 7?
Anni [7]

Answer:

in confused on what the question is asking is it multiple questions

4 0
2 years ago
Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.
ipn [44]

Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

3(8i + 15j + k) - 2(2i – 5j + 9k)

Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)

3(8i + 15j + k) = 24i + 45j + 3k

-2(2i - 5j + 9k) = -4i + 10j - 18k

-------------------------------------------------------------------------------------------------------------------

Simplify. Combine like terms

24i - 4i + 45j + 10j + 3k - 18k

(24i - 4i) + (45j + 10j) + (3k - 18k)

20i + 55j - 15k is your answer, or (C)

-------------------------------------------------------------------------------------------------------------------

hope this helps

5 0
2 years ago
Read 2 more answers
2 boxes has 50 pieces of candy and the other 2 boxes have 20 pieces of candy. how could ivanna solve for,c, the total number of
Norma-Jean [14]
C= 50y+20x
Where y is the number of boxes holding 50 pieces each and x is the number of boxes holding 20 pieces each.
7 0
3 years ago
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