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sladkih [1.3K]
3 years ago
5

1a/3a + 2 = 11 what does a equal

Mathematics
1 answer:
VashaNatasha [74]3 years ago
4 0
Because in the numerator and denominator of the fraction 1a/3a, you're able to simplify that and get 1/3. There is actually no solution to the problem you're asking. You're unable to find out what (a) equals. 
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PLZZ help me asap!! 70points!!
weqwewe [10]

Answer:

1. Given.

2. Opposite Sides OF A Parallelogram Are Congruent.

3. Corresponding Angles Postulate.

4. Substitution

5. ASA Congruence Postulate

6. Definition Of A Parallelogram.

Step-by-step explanation:

7 0
3 years ago
Mr. Hong brought his 7 year-old daughter, Jin and his 10 year-old son, Cai, to Redwood Amusement Park. An Admission ticket coste
kompoz [17]
$20.25 because 8.50 and 8.50 equal 17 and then subtract 2.00 makes 15, and then add 5.25 and you end up with 20.25
4 0
3 years ago
Which statement describes the symmetry of the data in the two box plots?
inysia [295]

Answer:

The data in country B are more symmetric than the data in country A.

Step-by-step explanation:

The following information is missing:

<em>The box plots show the average wind speeds, in miles per hour, for various cities in two different countries. Average Wind Speeds of Cities in Country A 2 box plots. The number line goes from 1 to 11. For the average wind speeds of cities in country A, the whiskers range from 1 to 9.5, and the box ranges from 3 to 7. A line divides the box at 4. For the average wind speeds of cities in country B, the whiskers range from 1.2 to 11, and the box ranges from 4 to 9. A line divides the box at 6. Average Wind Speeds of Cities in Country B</em>

Country A

  • minimum: 1
  • quartile 1: 3
  • median: 4
  • quartile 3: 7
  • maximum: 9.5

Country B

  • minimum: 1.2
  • quartile 1: 4
  • median: 6
  • quartile 3: 9
  • maximum: 11

We can see that the difference between quartile 1 and minimum, median and quartile 1, quartile 3 and median, and maximum and quartile 3 is more homogeneous in Country B than Country A, then Country B is more symmetric.

3 0
3 years ago
Read 2 more answers
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Shkiper50 [21]

Answer:

a) P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335

b) P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452

c) P(X \geq 8) = 1-P(X

d) P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that X \sim Poisson(\lambda=4)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda=4  , Var(X)=\lambda=2, Sd(X)=2

a. Compute both P(X≤4) and P(X<4).

P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183

P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733

P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465

P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646

P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692

b. Compute P(4≤X≤ 8).

P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595

P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298

P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452

c. Compute P(8≤ X).

P(X \geq 8) = 1-P(X

P(X \geq 8) = 1-P(X

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

4 0
3 years ago
If e || f and a || b, what is the value of y. *
Blizzard [7]

Answer:

y = 90

Step-by-step explanation:

Since, e || f and a || b

Therefore, quadrilateral so formed is a rectangle.

Each angle of a rectangle is right angle.

\therefore \: y \degree = 90 \degree \\  \\  \huge \red{ \boxed{ \therefore \: y  = 90}}  \\  \\

3 0
3 years ago
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