<u>Answer:</u> The equilibrium constant for this reaction is
<u>Explanation:</u>
The equation used to calculate standard Gibbs free change is of a reaction is:
For the given chemical reaction:
The equation for the standard Gibbs free change of the above reaction is:
We are given:
Putting values in above equation, we get:
To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:
where,
= standard Gibbs free energy = -32.9 kJ/mol = -35900 J/mol (Conversion factor: 1 kJ = 1000 J )
R = Gas constant = 8.314 J/K mol
T = temperature =
= equilibrium constant at 25°C = ?
Putting values in above equation, we get:
Hence, the equilibrium constant for this reaction is
Answer:
CO2
Explanation:
It is Carbon Dioxide that has its carbon atom covalently bound to 2 oxygen atoms.