Answer:
The correct answer is 3.36 L
Explanation:
The molecular weight of CO₂ is 44 g/mol (2 O + 1 C= (2 x (16 g/mol )) + 12 g/mol). We have 44 g in 1 mol CO₂, and we want to know how many mol are in 6.6 g:
44 g -------------- 1 mol CO₂
6.6 g -------------- X= 6.6 g x 1 mol / 44 g = 0.15 mol
In normal conditions of temperature and pressure, 1 mol of ideal gas occupies 22.4 L of volume, thus:
1 mol CO₂ ------------ 22.4 L
0.15 mol -------------- X= 3.36 L
So, 6.6 g CO₂ are equivalent to 0.15 mol CO₂ and they occupy 3.36 L.
It would use rapid combustion
Answer:
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Explanation:
Product:
C: 1
O:3
H: 2
reactant:
C: 8
H: 18
O: 2
first you need to put probably an eight in front of the Carbon.
Next, add a coefficient of 9 to Hydrogen
finally, add a 3 INSTEAD of a 2 to Oxygen
should look like:
C8H18+O3>C8O2+H9O