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artcher [175]
3 years ago
13

Jeffrey spent 2/3 hour on his homework how many minutes did he spend on home work

Mathematics
2 answers:
olganol [36]3 years ago
5 0
45 minutes because when you divide 60 minutes into sections you get 45 minutes
Nutka1998 [239]3 years ago
3 0
He spent 40 Minutes on his homework 1 Hour = 60Minutes so 60/ 3= 20 x 2 is 40
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5% times blank equals 2.5<br><br> NEED ASAP
lapo4ka [179]

Answer:

0.5

Step-by-step explanation:

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Mrs.smith earns $3500 a month. She saves $280 a month. Savings is what percent of her income?
arlik [135]

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3500 280

Step-by-step explanation:

280/3500

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its 8 her savings are 8 percent of her income

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Which table shows equivalent times in minutes and seconds
olchik [2.2K]
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If the triangle on the grid below is translated by using the (x,y) -&gt; (x+5, y-2) rule, what will be the coordinates of B'?
Art [367]
We know that
the coordinates of point B ( -5,0)

the translation has the following rule
(x,y)--------> (x+5, y-2)
so
(-5,0)-----> (-5+5,0-2)-----> (0,-2)

the answer is
<span>(0, –2) </span>
4 0
3 years ago
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The quadratic function g(x) = a.ca + bx+c has the
Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

f(x)=ax^2+bx+c

Here we know that the leading coefficient a=1 so we reduce our equation to:

g(x)=x^2+bx+c

The roots are those values at which g(x)=0

So:

x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\  49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\

Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\  49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0

So we have:

(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}

Finding c from (1):

33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0
3 years ago
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