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LenKa [72]
2 years ago
7

Find x of the triangle

Mathematics
1 answer:
sukhopar [10]2 years ago
5 0

Answer:

Step-by-step explanation:

altitude = sqrt(6*8) = 4*sqrt(3)

Use the Pythagorean Theorem to derive x

altitude^2 + 18^2 = x^2

48 + 18^2 = x^2

x^2 = 342

x = 3*sqrt(38)

x = 18.49

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Simplify: -8(7x + 4) + 10(3x)<br> helppppp
NeTakaya

Answer:

-26x-32

Step-by-step explanation:

distribute:

<u>-8 x 7x = -56x   -8 x 4 = -32   10 x 3x =30x</u>

<u>Simplify:</u>

<h2><u>-26 -32</u></h2>
7 0
3 years ago
What is the inverse of the function g(x)=x^3/8+16
shtirl [24]

Answer:

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

Step-by-step explanation:

Inverse of a function:

Suppose we have a function y = g(x). To find the inverse, we exchange the values of x and y, and then isolate y.

In this question:

y = \frac{x^3}{8} + 16

Exchanging x and y:

x = \frac{y^3}{8} + 16

\frac{y^3}{8} = x - 16

y^3 = \frac{x-16}{8}

y = \sqrt[3]{\frac{x-16}{8}}

The inverse of the function is f^{-1}(x) = \sqrt[3]{\frac{x-16}{8}}

7 0
3 years ago
May someone help me with this?
Colt1911 [192]

Answer:

30

Step-by-step explanation:

4 0
3 years ago
Three friends go to the local framers market. Latasha spends $3.35. Helen spends 4 times as much as Latasha. Dee spends $7.50 mo
mylen [45]

Given:

Latasha spends $3.35

Helen spends 4 times as much as Latasha.

Dee spends $7.50 more then Helen.

To find:

The amount Dee spends.

Solution:

It is given that, Latasha spends $3.35.

Helen spends 4 times as much as Latasha.

So, Helen spends = 4 × $3.35

                              = $13.40

Dee spends $7.50 more then Helen.

Dee spends = $13.40+$7.50

                    = $20.90

Therefore, dee spends $20.90.

8 0
3 years ago
Which expressions are equivalent to when x0? Check all that apply.
Genrish500 [490]
We have that

\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}

therefore

case a) 
\frac{(x+4)}{3} * \frac{x}{6}
Is equivalent

case b) 
\frac{6}{x} * \frac{(x+4)}{3}
Is not equivalent

case c) 
\frac{x}{6} * \frac{(x+4)}{3}
Is  equivalent

case d) 
\frac{(2 x^{2} +4x)}{6}
Is not equivalent

case e) 
\frac{(2 x^{2} +4x)}{18}
Is equivalent

Hence

the answer is

\frac{(x+4)}{3} * \frac{x}{6}

\frac{x}{6} * \frac{(x+4)}{3}

\frac{(2 x^{2} +4x)}{18}
3 0
2 years ago
Read 2 more answers
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