Sin J = cos K
sin J = cos (90 - J)
So, K = 90 - J
Therefore, 60 deg, 30 deg satisfy the condition sin J = cos K.
Answer:
A proof that square root of 2 is irrational. ... An equation x² = a, and the principal square root ... The number under the radical sign is called the radicand. ... the given square numbers, each product of square numbers is equal to what square ... are relatively prime -- and it will be impossible to divide n· n into m· m and get 2.
Step-by-step explanation:
Answer:

Step-by-step explanation:
We want to simplify:

We rewrite the expression under the radical sign to obtain:

We split the expression under the radical sign to get:

Recall that:

This implies that:

Therefore 
Answer:
1: -13
Step-by-step explanation:
First, simplify the equation to -2y+10=36
Subtract 10 from both sides
-2y=26
Divide negative 2 from both sides
y=-13