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Viktor [21]
3 years ago
8

HELP ASAP THIS IS TIMED ​

Mathematics
1 answer:
Kitty [74]3 years ago
7 0

C 3/4÷12

You Welcome :)

Answer: C

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What is the nth term of the sequence -2 -8 -18 -32 -50
andreev551 [17]

Answer:

-2n²

Step-by-step explanation:

Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
T_{n} = an^{2}  +bn +c

To find the value of a we just divide second difference ( -4 ) by 2:

  • a = \frac{-4}{2}= -2

Now we have:

  • T_{n}= -2n^{2}  +bn+c

Substitute n_{1} and n_{2} into the equation above:

  • T_{1} = -2(1)^{2}  +b(1) +c
  • T_{2} = -2(2)^{2}  +b(2)+c

Since T_{1} = -2 and T_{2} = -8 , after simplification we have:

  • b +c =0
  • 2b+c=0

The solution of this system is:

  • b=0, c =0

The general term is :

T_{n} = -2n^{2}

6 0
2 years ago
(√2+√3) ^2<br>answer faaaaaaaaaaaaast<br>​
ad-work [718]

Answer:

2.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Pls help me I am confused
Maslowich

Answer:

\huge\boxed{A.\ \dfrac{565}{182}}

Step-by-step explanation:

\dfrac{8}{7}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{8}{7}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by 35}\\\\35\cdot\dfrac{8}{7}-35\cdot5x+35\cdot3=35\cdot\dfrac{1}{5}x-35\cdot12\qquad|\text{simplify}\\\\5\cdot8-175x+105=7\cdot x-420\\\\40-175x+105=7x-420\\\\-175x+(40+105)=7x-420\\\\-175x+145=7x-420\qquad|\text{subtract 145 from both sides}\\\\-175x=7x-565\qquad|\text{subtract }7x\ \text{from both sides}\\\\-182x=-565\qquad|\text{divide both sides by (-182)}\\\\x=\dfrac{565}{182}

8 0
3 years ago
Read 2 more answers
What is the slope of a line given the points (4,-2) and (6, 5)?
Ksenya-84 [330]

Answer:

3 1/2

Step-by-step explanation:

5--2=7

6-4=2

7/2= 3 1/2

5 0
3 years ago
An equation of the line that passes through (3, 1) and (0, 10).
MrMuchimi

Answer:

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

Step-by-step explanation:

(3, 1) and (0, 10)

m=y²-y¹/x²-x¹

m=10-1/0-3

m=9/-3

m=-3

y=mx+b

y-y=m(x-x1)

y-1=-3(x-3)

y-1=-3x+9

+1 +1

y=-3x+10

3 0
3 years ago
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